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  1. Pasindu

    Computers & ICT: Post your doubts here!

    is this in the syllabus
  2. Pasindu

    Computers & ICT: Post your doubts here!

    ii] if the stack is implemented in a array you can just check whether the array is full or not iii] array is set of memory locations which is located adjacently to each other iv] i think there is serial access and there is direct or random access, the index sequential file can be accessed...
  3. Pasindu

    Computers & ICT: Post your doubts here!

    File is organized sequential with respect to the primary key, a record is associated with a number called index which is used to identify it. index are stored in the index file with the primary key , index is the pointer to the absolute memory location of the record Index sequential file can...
  4. Pasindu

    Computers & ICT: Post your doubts here!

    3 C The questions is when the program reads the letter how is it going to increase the counter, if it is in a one dimension arrary it will be like this VB 6 1: Dim arrary ( 1 to 26 ) 2: Letter_found = Lcase ( Letter_found) 3: Letters_num = ( Asc ( Letter_found ) - ( Asc ( " a" ) ) + (...
  5. Pasindu

    hodai guess your from SL

    hodai guess your from SL
  6. Pasindu

    Physics: Post your doubts here!

    Resultant is = [ 8 cos 20 ] x [ 6 cos 20 ] = 13.2
  7. Pasindu

    Physics: Post your doubts here!

    it's this in maths and not in physics
  8. Pasindu

    Physics: Post your doubts here!

    O/N 2010 paper 43, question 3a(i) d = -4.0 x cos ( 220 t) W= 2 x pi x f and W=220 then f = 35 then f = 1/ t then t = 1/35 Substitute and get the answer i think this is the way
  9. Pasindu

    Physics: Post your doubts here!

    What is eddy current this was help full to me It is the current induced in the conductor when there is a changing magnetic field Hope This is helpful
  10. Pasindu

    Physics: Post your doubts here!

    Q5 B ii - I think because Tesla is the magnetic flux density acting normal to the object in this case because they are parallel if you try resolving MFD normal to the object then it is MFD x cos 90 , which is equal to zero the answer is change is = 9.81 x 10 ^-5 Q 2 ii - acceleration and...
  11. Pasindu

    Physics: Post your doubts here!

    27 - The answer is zero because gravitational potential is work done to bring a unit positive charge from infinity point , therefore according to the equation of GP the radius must change to change the GP but here the GP is the same therefore zero hope this is helpful
  12. Pasindu

    Physics: Post your doubts here!

    Making scheme says D towards the observers but i also had the same answer can any one help
  13. Pasindu

    Physics: Post your doubts here!

    When resolving forces in any direction remember resolving towards the angle is - COS angle resolving away from the angle is - SIN angle This makes every thing easy ! Hope this is helpful
  14. Pasindu

    Physics: Post your doubts here!

    J04 P2 1 B - To get the resultant it is ( 8 cos 20 ) + ( 6 cos 20 ) = 13.2 error is 0.2 J 05 /P1 Q 3 - The velocity is 10 ms per second therefore when you calculate KE = 0.5 x 80 x 10 ² = Ans is 4000 which is answer B Q 11 - This is a perfect inelastic collision only momentum is...
  15. Pasindu

    Computing 9691 Paper 3 problem

    Do you have any sample question , you should know a programming language for paper 3 mostly VB. give me a question i'll be able to answere it
  16. Pasindu

    Computers & ICT: Post your doubts here!

    Total values 200 Hashing algorithm example ID is 2112123 Algorithm - 2112123 MOD 2000 = 123 [ This is the remainder of the division ] Hope This helps !!
  17. Pasindu

    Computers & ICT: Post your doubts here!

    Example of the fetch decode cycle of LDA [Load-in accumulator ] 200 in immediate addressing mode address in the PC [Program counter] is copied to MAR [Memory address register] address in the PC is incremented by 1 MDR [Memory data register] fetches the data in the address pointed to by the...
  18. Pasindu

    Computers & ICT: Post your doubts here!

    Differences are * ROM can be directly be accessed by the main memory but RAM cannot be * data in the RAM is lost when power is lost but data in the ROM is not lost when the power is lost [ RAM is volatile ROM is non Volatile ] * data in the ROM cannot be changed but data in the RAM can be...
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