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  1. M

    HELP ME ! MATHX PAPER 2

    InshAllah
  2. M

    HELP ME ! MATHX PAPER 2

    Area of circle inside a semicircle= pi x (r²/4), where r is the radius of the semicircle. area of the circle = 28.274 pi x rsquared = 28.27 r = underoot 28.27 / pi r= 3
  3. M

    HELP ME ! MATHX PAPER 2

    haha :P thanks just pray for me ! that i do good tommorow :/
  4. M

    HELP ME ! MATHX PAPER 2

    23b) perimeter = half circumference of circle + half circumference of semi circle + 6 = 34.3 cm
  5. M

    HELP ME ! MATHX PAPER 2

    23 ) diameter of semi-circle=12 radius of semi-circle=6 diameter of circle=6 radius of circle=3 area of circle ( the one inside the semi circle ) pi x 3squared =28.27433388 area of semi circle pi x 6squared =113.0973355 shaded area = area of semi circle - circle / 2 = 84.82300165 / 2...
  6. M

    HELP ME ! MATHX PAPER 2

    In these graphs the distance traveled is found by the area under the lines , so in this case there are two small triangles on top and a large trapezium triangle 1 - 0.5 x 20 x 6 = 60 triangle 2 - 0.5 x 10 x 6 =30 trapezium - 0.5 x (100+80) x 12 = 1080 1080+60+30 =1170 m
  7. M

    HELP ME ! MATHX PAPER 2

    21A ) you can either find the gradient of the line to find out the acceleration or use the acceleration formula : final speed - initial speed / time taken if you use the gradient method you get two co-ordinates of that line so in this case : (0,0) and (18,30) then substitute these values into...
  8. M

    Help being offered in busines studies and economics

    i haven't started studying economics or business yet ! i left them two and focused on sciences and computer studies now my time is so less im not sure what to do , can you please guide me ?
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