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  1. coolhudhayfahfaiz

    Chemistry: Post your doubts here!

    HBr + NaOH -----> NaBr + H20 n=cv=0.02 x 0.2 = 4 x10^-3 moles of HBr n of NaOH = cv= 0.015 x 0.2= 3 x 10^-3 moles. 1x10^-3 moles of HBr left. Assuming HBr is a strong acid, [H+] = 1x10^-3/0.02+0.015=0.0286 mol dm^-3 ph=-log[H+]=1.54
  2. coolhudhayfahfaiz

    Chemistry: Post your doubts here!

    Hi guys, I have a question regarding Fe+2 and KMnO4 titrations. So you do know that before carrying out the titration excess dilute sulfuric acid must be added to the Fe+2 solution to allow redox rxn to occur. But doesn't the addition of excess dilute sulfuric acid(mainly water) dilute the Fe+2...
  3. coolhudhayfahfaiz

    Physics: Post your doubts here!

    Bro the 2021 papers will come out exactly when the Indian student's AS and A level receives their grades from Cambridge. Idk what date is that on tho. SO,...
  4. coolhudhayfahfaiz

    Physics: Post your doubts here!

    Q25/. The distance between a node and an antinode is wavelength/4 meters. the frequency of this note is 75 hertz. v= frequency x wavelength. So, the frequency is equal to 75 = v/4L where L is the distance between a node and an adjacent antinode. L=wavelength /4. Wavelength = 4L. The v of the...
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