• We need your support!

    We are currently struggling to cover the operational costs of Xtremepapers, as a result we might have to shut this website down. Please donate if we have helped you and help make a difference in other students' lives!
    Click here to Donate Now (View Announcement)

Search results

  1. O

    Internship at UN

    hahahahahaha....... :crazy: INTERNSHIP PROGRAMME at UNIC Islamabad // To qualify, he/she must have at least completed one year of their under-graduate degree. To apply for an internship position with UNIC please send a brief cover letter and a copy of your curriculum vitae to: Internship...
  2. O

    chemistry 34 threshold

    It might have been right, but you forgot the fact that you would also have to confirm the presence of Aluminium, Zinc and Lead even when they gave the same results with NaOH. You wouldn't know that before doing it would you. So HCL would only be used to differentiate Aluminium and Lead after you...
  3. O

    Chemistry 9701/P22

    @m2rulz143- you are thinking that the ethanoic acid will first react with NaOH and the remaining would react with the alcohol. The NaOH was added in the end, so whatever moles of Ethanoic acid it reacted with was the one that REMAINED after reaching equilibrium...
  4. O

    Chemistry 9701/P22

    Sorry dude. I already explained the reason.The value of Kc was 2.25 or smthng not 0.44....as NaOH was 0.045 moles and 0.005 reacted with HCl. 0.04 reacted with Ethanoic Acid, meaning that 0.04 moles of Ethanoic Acid were there at equilibrium. So Both the reactants were of 0.04 and products at...
  5. O

    Chemistry 9701/P22

    yes, you would get the ecf mark. If you made a mistake on calculation but filled in the table and calculated Kc according to it, you would get all the marks except (stechiometric) calculation. if you made a mistake in just the table, you would get ecf on the Kc but no marks for table.....:P :Rose:
  6. O

    Chemistry 9701/P22

    The value of Kc was 2.25 or smthng not 0.44.( btw I wrote 0.44 )...as NaOH was 0.045 moles and 0.005 reacted with HCl. 0.04 reacted with Ethanoic Acid, meaning that 0.04 moles of Ethanoic Acid were there at equilibrium. So Both the reactants were of 0.04 and products at 0.06 concentration. 8)...
  7. O

    Mathematics 9709 paper 12 how was it with you?

    what was the vector angle? :oops:
Top