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  1. T

    Valuable tips for stats 1

    Thanks bro!
  2. T

    Physics p22

    OH and the circuit ques , the current was 2.5A , then 30watt , enery lost i did a vert silly mistake by not addind the power lost in battery A with the external resistance. But still the power lost was less than produced so the last question was proved that surplus energy was stored in battery B
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    Physics p22

    i did exactly what hassam bro said ( rain drop graph ) , Young modulous can be explained in lots of way as long as it makes sense. About the roller coaster question : Kinetic energy 27KJ , potential was proved 24KJ , therefore Energy lost due to resistive force 3KJ. the distance travelled at...
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    i wrote more than the given space

    <comment removed> REASON: Paper Discussion before 24 hours!
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    MATHS S1 paper62 idea and suggestion.

    MAY JUNE 2010 varient 62 , was indeed the toughest paper so far.
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    MATHS S1 paper62 idea and suggestion.

    Helo , does anyone have any idea what might come in MJ2011 S1 p62? as we can see theres a change in pattern of all questions , how should i get parfectly prepaired 4 it?
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    So how was Physics P33?

    The graph was positively increasing , how can it be -ve!!!?
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    Phy paper33

    My y intercept was .05 , some of my friends got -ve , how can time be -ve!!!???
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    Can someone explain to me the Kc in CHEp22?

    mine was .6square/.4square , but it should be the opposite .4sq/.6sq , and not sure about ommiting water.
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    Can someone explain to me the Kc in CHEp22?

    Balaj bro , i exactly did that in my exams , but a friend of mine explaned me this , the sample was titrated AFTER IT REACHED EQUILIBRIUM , that means IN EQUILIBRIUM .04 ethanoic was present and .06 reacted to form the ester.
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    Phy paper33

    Do you think 3 is correct ( our apparatus was not perfect mine was a bit slant ) and wb d y intercept???
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    Phy paper33

    You may get marks for calculation , what was ur gradient btw? mine was 3.
  13. T

    Can someone explain to me the Kc in CHEp22?

    Logically bro i got .44 too , . The amount of NaOH taken was .0045 , from there .005 reacted with HCl , leaving .04 for the ethanoic acid to get neutralised. as 1mol Naoh neutralises 1mol ethanoic acid so .04 would neutralize .04 mol of ethanoic acid WHICH WAS LEFT AND IT WAS NOT TURNED TO...
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