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  1. I

    P3 Urgent Help

    @ Well Wisher Integral of 1/Sqrt(x^3-x^4), Follow The Steps 1/Sqrt(x^3-x^4) = 1/sqrt (x^3(1-x)) Let x = sin^2u, Then dx = 2sinucosu du Substituting, We'll Have 1/Sqrt(sin^6u(1-sin^2u)) dx. dx = 2sinucosu du, so 1/Sqrt(sin^6u(1-sin^2u)) * 2sinu cosu taking Squareroot : 1/(Sin^3u(Cosu)) *...
  2. I

    p3 tough question

    Nothing Is Tough Buddy. Infact, We Make Things Difficult. You Just Need To Concentrate A Bit... Do It This Way: First Express The Equation on The LHS In Terms Of RSin(u+a), Where u=2x & a is a constant. You're Gonna Get 3cos2x + 4sin2x = 5Sin(u+36.87), Where R = 5 And a = 36.87 Now, Put...
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