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24 hr ban over, phy pap52

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gradient = F, value = 1190
for q1, plot a graph of q^2 against p and v = square root (0.5 x g x gradient)
 
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i made a mistake in independent variable!how many marks i will lose?i misunderstood the question!my independant is v square!and dependant is right!
 
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Q1. independnt P .. Dependent Q ... controlled .. Density of ball, initail speed of ball etc ...
> method.. diagram + explainatoin
> Analysis.. plot a graph of lgq against lgp^2 if satisfies equation .. a straight line is obtained..
> Safety .. keep a distance .. use sandbags
> improvemnts .. many :p

Q2. Gradient=F = 1.2x10^3 unc 0.1x10^3 ..... V/E = 11 ... and predicted value for V = 17.6 . uncertainities in table 0.6 to 0.2 ...
 
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for q1..
i wrote p is independent and q was dependent and stuff like dat..

for q2
gradient= F
gradient= (1.21 +-0.15) x 10^3
ummm v/e mayb 11 dun remember well....


how can gradient b F+1 ??? want 1 the y intercept??
 
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em sry ijux cant remember it..may be like 1. something i dun remember!! :S
 
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i gat the same value of v/e mines was 10 uncertainity was like .2 ....my gradient was f+1....bt i think i messed it up a lot...:(
 
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