9709/52 Q2-b how to find absolute uncertainty

[talha-_-khan]

How to do we find the absolute uncertainty , would appreciate if some one showed the steps

 

[talha-_-khan]

please some one answer

 

[adityar]

Thats pretty easy dude, you calculate your normal values by 1/L , that you know. For the first one for eg.:
Value needed = 1/(54.5 x 10^-2) = 1.83
Then unc= 1/(55 x 10^-2) MINUS 1/(54.5 x 10^-2) = 0.017 so unc.= +/- 0.017

What I did is, calculate the original value, then calculate your most extreme value; uncertainty = Max. value - Best value
BTW, do you take engish?

 

[talha-_-khan]

Thats pretty easy dude, you calculate your normal values by 1/L , that you know. For the first one for eg.:
Value needed = 1/(54.5 x 10^-2) = 1.83
Then unc= 1/(55 x 10^-2) MINUS 1/(54.5 x 10^-2) = 0.017 so unc.= +/- 0.017

What I did is, calculate the original value, then calculate your most extreme value; uncertainty = Max. value - Best value
BTW, do you take engish?

thanks

 

[talha-_-khan]

Thats pretty easy dude, you calculate your normal values by 1/L , that you know. For the first one for eg.:
Value needed = 1/(54.5 x 10^-2) = 1.83
Then unc= 1/(55 x 10^-2) MINUS 1/(54.5 x 10^-2) = 0.017 so unc.= +/- 0.017

What I did is, calculate the original value, then calculate your most extreme value; uncertainty = Max. value - Best value
BTW, do you take engish?

 

[talha-_-khan]

no i did not take english ( i took maths , physics and computing ) yes it seems that i am an idiot to ask how to calculate uncertainty of such an easy question but you know it happens

 

[adityar]

Haha no probs I take phy maths chem bio eng it... Its crazy.. But I dropped it after AS

 

[Jinkglex]

what i do for these questions is i take the uncertainty in the original table value and then multiply it with my 1/h or whatever is in the second table...the answers are always correct...