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IN nov 2011 v3 paper 3

Q 2 b ii

how to get the E column
Heterozygous mating with heterozygous produces 3:1 ( Without tail : with tail )
add the O results which will bd 112 so that the E for with tail would be ( 112*1 )/4 = 28
and for without tail (112*3) / 4 = 84 :D
 
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Heterozygous mating with heterozygous produces 3:1 ( Without tail : with tail )
add the O results which will bd 112 so that the E for with tail would be ( 112*1 )/4 = 28
and for without tail (112*3) / 4 = 84 :D
thx ! u saved the day
 
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