A2 Physics | Post your doubts here

[princesskt]

its that e.m.f is -ve d(phi)/dt

so if gradient is decreasing than doesnt it means that the emf will become more negative.....................so it must go down...yes or no?

 

[hassam]

suggest why alchol and mercury thermometers give different readings at the same temp?

 

[namename]

its that e.m.f is -ve d(phi)/dt

Huh? then the graph should look like this then (for a to b)

 

[smzimran]

Unless someone answers it, I will be solving 2010 tomorrow.

???

 

[princesskt]

Huh? then the graph should look like this then (for a to b)View attachment 8837

thats also not correct ..............it must become more negative,,,,,,what i think so.........

 

[smzimran]

suggest why alchol and mercury thermometers give different readings at the same temp?

AoA,
The specific heat capacity of mercury and alcohol is different, so they need different amounts of heat to raise the temp by 1 unit

 

[princesskt]

suggest why alchol and mercury thermometers give different readings at the same temp?

they both have d/f physical properties and donot varry linearly with absolute scale so both will give temp.....

 

[hassam]

well in half wave rectification......during the half in which diode is reverse biased,,,,,,how the potential varies acroos diode?
, gettimg cnfused in this ....tell me the concept

 

[smzimran]

well in half wave rectification......during the half in which diode is reverse biased,,,,,,how the potential varies acroos diode?

Max potential across diode as its resistance is infinite
Because it does not allow current flow

 

[hassam]

Max potential across diode as its resistance is infinite
Because it does not allow current flow

well wud it be varying like -ve half of sine wave or not?

 

[namename]

thats also not correct ..............it must become more negative,,,,,,what i think so.........

I guess its correct; Think as if that original graph can be represented as sin graph. then emf would be -cos graph for the particular range

 

[namename]

Help anyone?

 

[princesskt]

I guess its correct; Think as if that original graph can be represented as sin graph. then emf would be -cos graph for the particular range

ok that means emf becoming less negative as gradient decreasing from V vs x graph i.e like if 1.5 changes to 1.2 (suppose gradient) than with -ive -1.5 & -1.2 value increasing........corrrect me if i m wrong....hassam ones is right..

 

[princesskt]

View attachment 8850View attachment 8851Help anyone?

i=2 Hz(1/.5)
ii=1 V
iii=4 bits

 

[namename]

i=2 Hz(1/.5)
ii=1 V
iii=4 bits

How did u get the answer for i) ??

 

[namename]

Help

 

[smzimran]

well wud it be varying like -ve half of sine wave or not?

No, it wont be

 

[SkyPilotage]

???

Starting Nov 2010 41 now, will answer you in a couple of hours hopefully. Sorry for the delay...

 

[princesskt]

HelpView attachment 8855 View attachment 8854

initially zero(because zero inside sphere) than it would be with same shape but little more curved i m 100% sure saw it in a book.......

 

[smzimran]

Starting June 2010 now, will answer you in a couple of hours hopefully. Sorry for the delay...

I have solved it, found a logic myself bro,
But you do solve for me too, maybe our logics will match
Thanks bro