Add Maths now!

[ibadsiddiqi]

Ok so now we have addmaths! If anyone has any queries, questions or know anything important then please do share..

 

[abc123]

Could you help me out with the following in http://www.xtremepapers.me/CIE/Cambridg ... _qp_12.pdf:
5 part 2, 7b, 8 and 10 plese

 

[ibadsiddiqi]

@abc123 post the link again..i cant access it

 

[abc123]

http://www.xtremepapers.me/CIE/Cambridg ... _qp_12.pdf

i got the rest. Could you just do 7b and 11 part 2 and 3

 

[ibadsiddiqi]

Q.7) you solve it like a normal trigonometry question
the range is 0 (less then or equal to) x (less then or equal to 180)
so the range of 3x will be 0 (less than or equal to) 3x (less than or equal to) 540

now you solve the equation: sec^(2) 3x= 1
cos^(2) 3x=1
cos3x= +/- 1
3x= 0, 180, 360, 540
x= 0, 60, 120, 180
hence n(C)= 4

Q-11) ii) and iii) I am so sorry but i cant explain it over here however check the mark scheme, its really helpful http://www.xtremepapers.me/CIE/Cambridg ... _qp_12.pdf
I know i wasn't of much help so sorry once again

 

[abc123]

i don't get it from the marking scheme thats why i posted it here

 

[adnanj]

please explain the Conrad Dickens and Shakespeare question in Add Maths book in permutation and combination??

 

[iFuz]

@adnanj

a) total books = 9
conrad = 3
if these books are next to each other thn= 3!
and remaining books are 6 but we have to consider conrad as one group so we'll get it as 1 and that makes total books = 7
so, 3! x 7! = 30240

b) if books of dickens are together thn do the same what we did in part a)
we would consider 2 as one group and total number would be 8 now

2! x 8! = 80640

but we want to get that if they are seperated so,
total arrangements - if they are together
9! - 80640 = 282240

c) do the same

if they are together thn = 30240

separated = total - together
= 9! = 30240
= 332640

 

[adnanj]

@adnanj

a) total books = 9
conrad = 3
if these books are next to each other thn= 3!
and remaining books are 6 but we have to consider conrad as one group so we'll get it as 1 and that makes total books = 7
so, 3! x 7! = 30240

b) if books of dickens are together thn do the same what we did in part a)
we would consider 2 as one group and total number would be 8 now

2! x 8! = 80640

but we want to get that if they are seperated so,
total arrangements - if they are together
9! - 80640 = 282240

c) do the same

if they are together thn = 30240

separated = total - together
= 9! = 30240
= 332640

Answer of part C doesn't match with the book's answer

 

[iFuz]

that maybe wrong because our method is 100% correct.!!!!

 

[falcon678]

ok.....i wanted to ask whether add maths is feasible if i take FSc in Pak??????

 

[princesszahra]

ok.....i wanted to ask whether add maths is feasible if i take FSc in Pak??????

u want to do addmaths after FSC?
is that what u r asking?

 

[falcon678]

no i wanna take add maths in o levels.........but am doin FSc after it......

 

[princesszahra]

no i wanna take add maths in o levels.........but am doin FSc after it......

u can do it!

 

[123add1]

no when you subtracted it frm the total arrangements it also included the arrangement in which 2bks r together and 1 is seperated.

 

[donor]

can someone help me with Q#3
http://www.xtremepapers.me/CIE/Cambridge O Levels/4037 - Additional Mathematics/4037_w10_qp_21.pdf

 

[Diamona151294]

Hey can some one please help me in Q7b of this?
http://www.xtremepapers.me/CIE/Cambridg ... 6_qp_2.pdf

the answer is 50
its from permutations....

 

[Diamona151294]

can someone help me with Q#3
http://www.xtremepapers.me/CIE/Cambridge O Levels/4037 - Additional Mathematics/4037_w10_qp_21.pdf

As N(0) is the original number of fish then N in this case will be equal to N(0)/2
so the eq will be

N(0)/2=N(0)e^-k(34)

Solving this N(0) on both sides gets cancelled and u r left with

1/2=e^-k(34)

Take ln on both sides and u get the answer k=0.0204.

Hope this helped.