yup thats what i got tooo...littlecloud11 said:berryria said:wat was the values of a n b in linear law ques..2ns part?
A was 100 and B was 1/5
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yup thats what i got tooo...littlecloud11 said:berryria said:wat was the values of a n b in linear law ques..2ns part?
A was 100 and B was 1/5
vishal said:Does anyone else remember the ans to da either part of last que??? I remember the coordinates of A which we had to find in the first part were (0,5) .... In the next part we had to find the coordinates of C and D..... For C we had to find the equation of normal at B which meets the x-axis at C... By putting y= 0 into the eq of normal we had to find to coordinates of C. For D we had to simultaneously solve the eq of normal and tangent at x= -1 .... Is my method correct????????? I got 2 unit2 as answer by this method.... If my method is correct how many marks for method will I get out of 7???? Plzz tell me...... Iam very tensed....
vishal said:Is my method correct???? Besides if i have got the coordinates of A wrong so how many marks will I lose in the first part out of 3??? Do u remember the coordinates of C and D ????
mostly correct but howd you get the last answer in perm. combination ...i cant remember my answer...123add1 said:the co ordinates of A were 0,5.the coordinates of C were -5,0 .the coordinates of D were 20,5.so the area was 50 sq units.
What did u all get for the value of A??
what was the unit vector parallel to AB??and what was the position vector of C??
i got 24/25,-7/25 as the unit vector and 41,16.5 as the position vector.
the value of K=-2
the combinations were 3003,1050 and 364.
lgy=0.2x+2
a=100 and b=0.2
the radius was 15 and the shaded area was 105.1
A=1/6
stationery point was 1,-9
the angles were 19.5,160.5 and 25.7,115.7 and pi/2 ,7pi/6
AM I CORRECT???
vishal said:Do u remember the eq: of curve????
it was 3x^3 + 2x^2 - 5x + 1littlecloud11 said:vishal said:Do u remember the eq: of curve????
3x^3 + 2x^2 -5x +5
123add1 said:the co ordinates of A were 0,5.the coordinates of C were -5,0 .the coordinates of D were 20,5.so the area was 50 sq units.
What did u all get for the value of A??
what was the unit vector parallel to AB??and what was the position vector of C??
i got 24/25,-7/25 as the unit vector and 41,16.5 as the position vector.
the value of K=-2
the combinations were 3003,1050 and 364.
lgy=0.2x+2
a=100 and b=0.2
the radius was 15 and the shaded area was 105.1
A=1/6
stationery point was 1,-9
the angles were 19.5,160.5 and 25.7,115.7 and pi/2 ,7pi/6
AM I CORRECT???
vishal said:Are u sure abt this eq???? Because at x=-1 the y coordinate is 9 bt as far as I remember the y coordinate of A was 5.....
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