Additional Mathematics (0606) Doubt

[XxChampXx]

Why are u ONLY doing graphs question? Just give me an hour or so I will help ya out once I reach home.

Hahaha.....Actually I am doing past papers but I always get stuck on a few tricky questions.

 

[XxChampXx]

Do u understand relative velocity?? It is kind of confusing! and the diagram questions with them.

Yeah relative velocity is really hard. Sometimes I get confused in the velocity vectors part also(i, j, k questions).

 

[The_Boss]

Can you help in in May June 2012 QP12 question 11 part (i). Thank you in advance.

Link:- https://drive.google.com/folderview...sp=drive_web&tid=0BzumkDfi9230cS1pd0xaVWFGN0k

Here u go
Just a hint. Whenever u get decimal answers make sure u round them off so that they have same sf as the points in question like I got 2.96133..... I just round it off to nearest whole number as all x values are whole number

 

[The_Boss]

Yeah relative velocity is really hard. Sometimes I get confused in the velocity vectors part also(i, j, k questions).

There is no k in our syllabus! So what exactly do u find hard ?

 

[The_Boss]

And one more thing, u take the (3,1) coordinates for P because the question says that p is on the line AB and it's clear that the other point for p is beyond A

 

[The_Boss]

Yeah my school provides it.

That's interesting! I have never seen a school that provides add maths as a course in my region. Where do u live?

 

[XxChampXx]

Here u go
Just a hint. Whenever u get decimal answers make sure u round them off so that they have same sf as the points in question like I got 2.96133..... I just round it off to nearest whole number as all x values are whole number

That is hardcore algebra. Thank you so much.

 

[XxChampXx]

Here u go
Just a hint. Whenever u get decimal answers make sure u round them off so that they have same sf as the points in question like I got 2.96133..... I just round it off to nearest whole number as all x values are whole number

Do you have any other tips for these kind of questions?

 

[The_Boss]

Do you have any other tips for these kind of questions?

Just remeber to draw a sketch and learn a little bit of circle theorem and applications in Geometry. If you can try to download C2 Textbook for AS lvl(edexcel board) and read 4th Chapter Coordinate geometry in cartesian plane. Ik its as lvl just dont panic and read through the chapter it will reallly help you out in finding strategies to solve such problems as these type of question have more than a way to solve them and I preferably like to solve through substitution method.

 

[XxChampXx]

Just remeber to draw a sketch and learn a little bit of circle theorem and applications in Geometry. If you can try to download C2 Textbook for AS lvl(edexcel board) and read 4th Chapter Coordinate geometry in cartesian plane. Ik its as lvl just dont panic and read through the chapter it will reallly help you out in finding strategies to solve such problems as these type of question have more than a way to solve them and I preferably like to solve through substitution method.

Yeah I got the PDF. The book looks informative and has a bit of explanation on circle related problems. Thank you.

 

[XxChampXx]

Can u post a link to the pdf??

https://drive.google.com/folderview?id=0B2WyhNhKqN_eUThaTDl1VWQwZ0k&usp=sharing
It is the third book. Good luck for your exams.

 

[The_Boss]

So did u guys do ur paper1 yet?

 

[XxChampXx]

Nope!Mine is in 2hrs 30 minutes! And i am totally confused about interception problems

Which variant are you doing?

 

[nimo69]

i have a question for addmaths this came in p1.
Q. two teams each of four students are to be selected from 8 boys and 6 girls.
find the number of different ways they can be selected
i. if there are no restrictions
ii.one team contains girls only and the othere contains boys only.

 

[Rizwan Javed]

i have a question for addmaths this came in p1.
Q. two teams each of four students are to be selected from 8 boys and 6 girls.
find the number of different ways they can be selected
i. if there are no restrictions
ii.one team contains girls only and the othere contains boys only.

1) 14C4 * 10C4
2)8C4*6C4

 

[nimo69]

1) 14C4 * 10C4
2)8C4*6C4

could you please explain me that because I did i.14C8 and ii.8C4 plus 6C4

 

[Rizwan Javed]

could you please explain me that because I did i.14C8 and ii.8C4 plus 6C4

I think my second one is wrong it was to be a plus. i didn't noticed that. :/

 

[Rizwan Javed]

See ur first part is correct but second partnis wrong.
This is because you actually assumed that ur first choice doesnt effect you second choice but it does as ur choices arent independent of each other.

Hey can you please tell me which answers are correct for this question:
(i) 14C8 OR 14C4*10C4 (i did the first one; but my brilliant fellow did the 2nd)
(ii) 8C4*6C4 OR 8C4+6C4

This was the question:

Q. two teams each of four students are to be selected from 8 boys and 6 girls.
find the number of different ways they can be selected
i. if there are no restrictions
ii.one team contains girls only and the othere contains boys only.

 

[The_Boss]

Hey can you please tell me which answers are correct for this question:
(i) 14C8 OR 14C4*10C4 (i did the first one; but my brilliant fellow did the 2nd)
(ii) 8C4*6C4 OR 8C4+6C4

This was the question:

Q. two teams each of four students are to be selected from 8 boys and 6 girls.
find the number of different ways they can be selected
i. if there are no restrictions
ii.one team contains girls only and the othere contains boys only.

See the question said that TWO teams have to be choosen, so think of two teams as one conplete event(or outcome) ,and a single team as half of an outcome,and if u know the basic counting principle it says that if two tasks are to occur in succesive than u MULTIPLY their odds, and by this the first part is 14C8 and second is 8C4*6C4

 

[Rizwan Javed]

thnkx alot sir! thank god i did it correctly. i was too much worries about it.

See the question said that TWO teams have to be choosen, so think of a two teams as one conplete event(or outcome) ,and a single team as half of an outcome,and if u know the basic counting principle it says that if two tasks are to occur in succesive than u MULTIPLY their odds, and by this the first part is 14C8 and second is 8C4*6C4