Addmaths paper 1

[Bilal Khan]

Yeah I know but i left it unsolved coz i was confused...
My friends got P as -4.61 something and what about proving the trignometric equation?

u needed to expand the equation and solve it then..

 

[*Anonymous*]

well , i proved it .. but not with the right method..

lol, you know what I did? I just put values of angles in the question and then solved... LOL

 

[Bilal Khan]

lol, you know what I did? I just put values of angles in the question and then solved... LOL

Level bro !!

 

[Ishrar Afrida]

Was c0-ordinate of P -4.6?

 

[Bilal Khan]

Was c0-ordinate of P -4.6?

nah...
u had to differentitate 3tan x to form 3sec^2 x ..

 

[Moiz Awan]

Yup.

 

[Bilal Khan]

Yup.

nopes..

 

[Ishrar Afrida]

LOL ironically I did the differentiation part but put the value of x in normal equation -_- FML.

 

[Saad Mughal]

Was c0-ordinate of P -4.6?

Yeah. -4.61.

 

[Bilal Khan]

LOL ironically I did the differentiation part but put the value of x in normal equation -_- FML.

 

[Bilal Khan]

Yeah. -4.61.

how ??

 

[Saad Mughal]

how ??

The differential of y = 3 tan x - 2 was dy/dx = 3 sec^2 x, when you put x = 3pi/4, this becomes 6.
Gradient of normal = -1/6.
y + 5 = -1/6 (x-3pi/4)
6y + 30 = -x + 3pi/4 --> Eq. of normal.
Put x = 0
6y = 3pi/4 - 30
y = (3pi/4 - 30)/6 = -4.61

 

[Bilal Khan]

The differential of y = 3 tan x - 2 was dy/dx = 3 sec^2 x, when you put x = 3pi/4, this becomes 6.
Gradient of normal = -1/6.
y + 5 = -1/6 (x-3pi/4_
6y + 30 = -x + 3pi/4 --> Eq. of normal.
Put x = 0
6y = 3pi/4 - 30
y = (3pi/4 - 30)/6 = -4.61

oh man , i did everything right , just i got y= -1

 

[Ishrar Afrida]

The differential of y = 3 tan x - 2 was dy/dx = 3 sec^2 x, when you put x = 3pi/4, this becomes 6.
Gradient of normal = -1/6.
y + 5 = -1/6 (x-3pi/4_
6y + 30 = -x + 3pi/4 --> Eq. of normal.
Put x = 0
6y = 3pi/4 - 30
y = (3pi/4 - 30)/6 = -4.61

Holy Shit!! Can't believe it's right. ^_^ THANKS!!

 

[Saad Mughal]

oh man , i did everything right , just i got y= -1

You solved it in RADIANS or degrees?

 

[Bilal Khan]

You solved it in RADIANS or degrees?

radians man..

 

[Ishrar Afrida]

And and last question, what was the speed and distance of the particle?

 

[Bilal Khan]

And and last question, what was the speed and distance of the particle?

speed was 72 m/s and distance 864 m...

 

[Saad Mughal]

radians man..

Then how did you get it wrong?

 

[Saad Mughal]

And and last question, what was the speed and distance of the particle?

864 m.
324 m/s.