the K values are for the geometric progression, q10
m and P values are for q3
area is for q11 part (ii)
-
We need your support!
We are currently struggling to cover the operational costs of Xtremepapers, as a result we might have to shut this website down. Please donate if we have helped you and help make a difference in other students' lives!
Click here to Donate Now (View Announcement)
AFTER 24 hr .. P1 discussion here !
- Thread starter ahmed abdulla
- Start date
m and P values are for q3
area is for q11 part (ii)
- Messages
- 143
- Reaction score
- 93
- Points
- 38
Nicee wat do u expect the gt to be ??
- Messages
- 154
- Reaction score
- 88
- Points
- 38
- Messages
- 154
- Reaction score
- 88
- Points
- 38
It's going to be in the 50's.
I had a long chat with my big brother(who gave his AS maths paper last year in M/J 2012)
He said his paper was fairly difficult too.
the gt for his paper was 58/60.
I've attempted that paper, and tbh, didn't find it as tricky as our's.
insha ALLAH.
In Sha Allah.
Pray that the rest of us get A's too.
I really did messed up that coefficient of x^2 question part (ii)
corrected it just at the last half a minute or even less, and in the process of hurrying did a lot of scribbling, I hope the examiner understands the answer 40. Itmite lead to a 1 mark deduction as well
- Messages
- 154
- Reaction score
- 88
- Points
- 38
Ah, so I wasn't the only who got it wrong at first.
I don't think scribbling results in a lose of marks, I remember reading an examiner report saying "Some candidates got a hint of what the answer to part (i) would be thanks to part (ii) and so returned to rectify their incorrect answers."
Usually they ask us to find the coefficients required for the second part in part 1.
But this time we had to do a bit more
Alright guys, since 24 hours are up, these are some of the answers I remember of mine (Paper 12)
2(i) co-efficent of x^2 was either 64 or 60 (cant remember exactly)
(ii) coefficent was 124
3 m= -3 and P = (2,8)
4 (ii) Perimeter=20.4
(iii) 7.96 Area of shaded region
5 (i) [a^2 +b^2] The constant was being proved to be 10
(ii) 116.6 and 296.6
7 R(7,15)
10 (i) 25 terms
(ii) -21 and 63
11 (i) y=-0.5x+1
(ii) 7/6
Note=I am not saying any of these answers are correct but this is what I wrote. Please tell me which I got correct or wrong.
2(i) co-efficent of x^2 was either 64 or 60 (cant remember exactly)
(ii) coefficent was 124
3 m= -3 and P = (2,8)
4 (ii) Perimeter=20.4
(iii) 7.96 Area of shaded region
5 (i) [a^2 +b^2] The constant was being proved to be 10
(ii) 116.6 and 296.6
7 R(7,15)
10 (i) 25 terms
(ii) -21 and 63
11 (i) y=-0.5x+1
(ii) 7/6
Note=I am not saying any of these answers are correct but this is what I wrote. Please tell me which I got correct or wrong.
your anser no. 2 part (ii) is incorrect, and the trig. angles are incorrect I guess
the angles were 98.1 and 278.1 in my case
I got it p=-6 and q=6
- Messages
- 143
- Reaction score
- 93
- Points
- 38
Trignometry q the range ws given frm 0 to 360 rite ??
- Messages
- 143
- Reaction score
- 93
- Points
- 38
Yah me too...
Sorry Sorry, I got the same aswell
- Messages
- 143
- Reaction score
- 93
- Points
- 38
Wat about the trignometry range in q it 0 to 360 rite??
- Messages
- 36
- Reaction score
- 9
- Points
- 8
^agree
- Messages
- 77
- Reaction score
- 43
- Points
- 28
I did the same thing as you
I don't think zero is a domain. Cuz range was >=1, it would reach close to zero but not zero as such.
- Messages
- 143
- Reaction score
- 93
- Points
- 38
Wasnt it tan inverse of -7 ??
- Messages
- 36
- Reaction score
- 9
- Points
- 8
- Messages
- 143
- Reaction score
- 93
- Points
- 38
So arent we suppose to take it fr the - ve sign as well the other two ranges ??