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AS Biology P1 MCQs Preparation Thread

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Resolution means the ability to distinguish between two different points. With a resolution less than 7 nm, you won't be able to differentiate the membrane from its surroundings, you won't see it.
But you aren't seeing the membranes. Your simply looking at the lines of the cell which you can see. And which are 300nm apart
 
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Which of the following can result in heart failure?
1 increase in blood pressure
2 deposits of fatty material in arteries and veins
3 reduced oxygen supply to cardiac muscle
4 increased risk of blood clotting
A 3 and 4 only
B 1, 2 and 3 only
C 1, 2 and 4 only
D 1, 3 and 4 only
 
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Which of the following can result in heart failure?
1 increase in blood pressure
2 deposits of fatty material in arteries and veins
3 reduced oxygen supply to cardiac muscle
4 increased risk of blood clotting
A 3 and 4 only
B 1, 2 and 3 only
C 1, 2 and 4 only
D 1, 3 and 4 only

D
 
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But resolution= wavelength / 2. So the resolution of a 600nm wavelength should give a 300nm resolution. And since resolution is the ability to distinguish between 2 points then 2 membranes 300 nm apart should be seen as separate points..
Right?

nope...the membranes are 7nm....how can you see them with 300nm resolution? even though they are 300nm apart they it dsnt matter if you cant see them how can you distinguish them as seperate points?
 
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Mm, I don't usually have questions in biology, but can somebody explain the heart graph thing to me? When does the semi lunar valve open/atriolventricular valve open, etc?
 
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://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Biology (9700)/9700_s11_qp_12.pdf q6,8,9,21,30,35, anyone plz ?????/ :cry:

q-21 see the table. on the ryt hand side anticodons on the tRNA are written. First write the amino acid sequence while seeing the anticodon.
For ex the first one is UUA. the amino acid which will fit in the active site of this tRNA is AAU. and then there is a point that the sequence of the amino acid in the active site of the tRNA is same as the sequence in the DNA molecule.Only the U is replaced by G.
Hope u understand.
 
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help may june 2007 q4

Calibrate it first. Each division is 0.1mm and there are 50 EPG units for each 0.1mm division. Therefore one eyepiece graticule unit is (0.1/50) 0.002mm. (2 micrometers). Take the seed that is growing vertically. On the left picture the bud is at 25 EPG units. It grows to 35 EPG units. That's a difference of 10 EPG units. (10 * 2) = 20 micrometers in 4 hours. So 20/4 = 5 micrometers/hour
 
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Which symptoms may be seen in a person affected by chronic obstructive pulmonary disease
(COPD)?
1 persistent cough
2 less elastic alveoli
3 increased risk of lung infection
4 shortness of breath
 
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