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Guys im finiding paper 1 so tough. i am repeating it this year and i still have it as a big problem any tips?
Hey anyone can help?
June 2004 q33
8 should be D coz Starches do not react or react very poorly with Benedict's reagent, due to the relatively small number of reducing sugar moieties, which occur only at the ends of carbohydrate chainshttp://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Biology (9700)/9700_s06_qp_1
someone please help in. q: 8,16,17,20,23,22,24 and 25.
16 should be C coz larger the size of molecule lesser is diffusion same with diffusion.http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Biology (9700)/9700_s06_qp_1
someone please help in. q: 8,16,17,20,23,22,24 and 25.
Humidity means it is a quantity that represents the amount of water vapour present in atmospheric air.http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Biology (9700)/9700_s06_qp_1
someone please help in. q: 8,16,17,20,23,22,24 and 25.
"resting" muscles means that the partial pressure of O2 is high and partial pressure of Co2 is low, which means there will be no Bohr's shift. So B and C are blunder..please explain why A and not D?View attachment 51371
sorry the answer given is D and my question is why not A"resting" muscles means that the partial pressure of O2 is high and partial pressure of Co2 is low, which means there will be no Bohr's shift. So B and C are blunder..
Now as we know that HB realeases the oxygen when partial pressure of Co2 is high and partial pressure of O2 is low... so in resting muscle very less oxygen is released Hence the Ans in A.
If the statement was what is the %age saturation of HB when blood passes through an actively respiring muscle, the Answer would have been "C"..
Hope this Helps...
Still then ans is D its just that there will be no bohrs shift... Arguments will the same with just a mere change that at body cellular level haemoglobin nearly looses all O2 and if it is an actively respiring muscles where partial pressure of CO2 is too high then Bohr's shift occurs and tgen the ans is Csorry the answer given is D and my question is why not A
Still then ans is D its just that there will be no bohrs shift... Arguments will the same with just a mere change that at body cellular level haemoglobin nearly looses all O2 and if it is an actively respiring muscles where partial pressure of CO2 is too high then Bohr's shift occurs and tgen the ans is C
yes!does that imply that be it a actively respiring or resting tissue, the % saturation has to be low and haemoglobin has to lose 50% of its oxygen no matter it is a actively respiring or a resting tissue?
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