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AS maths pastpaper question help!
- Thread starter lightic
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Is there any mistake in winter 2012 question: 1 .qp11?
Nope
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ok, first find the vertex (-b/2a) x=2,y=2
now substitute these values in complete square form a(x-x)^2 + y, which becomes 2(x-2)^2 +2,
from here its much easier to get an inverse since all you have to do is send everything (except for x) to the other side, becomes = (y-2/2)^.5 +2,
and good luck on tmrw's exam
now substitute these values in complete square form a(x-x)^2 + y, which becomes 2(x-2)^2 +2,
from here its much easier to get an inverse since all you have to do is send everything (except for x) to the other side, becomes = (y-2/2)^.5 +2,
and good luck on tmrw's exam
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I am not good at explaining but hope it helps: you find the gradient of the line, then find the gradient of a perpendicular line, substitute the values of C in it to find the equation of the line passing throw C, Find the point of intersection of the two lines , then find how far is C from point of intersection and use it to find the mirror point.
