As physics p1 MCQS YEARLY ONLY.

[Bluejeans#]

kindly explain dis

 

[Raweeha]

View attachment 28788

kindly explain dis

Okay, this is from s12 p12 ...
It's fairly straight forward. You see that each pulse or 'peak' last for two cm on the horizontal axis. You also see the horizontal axis is calibrated 1us/cm. Multiply the two values and you get 2us. Clear, I hope?

 

[talha-_-khan]

Marking Scheme says the answer is A but i am getting C

 

[khoshi]

see

Marking Scheme says the answer is A but i am getting C

see they both are travelling in OPPOSITE directions so 20x6 - 12x15 = (20+12)v And hence v =1.875 whixh is 1.9

 

[talha-_-khan]

see
see they both are travelling in OPPOSITE directions so 20x6 - 12x15 = (20+12)v And hence v =1.875 whixh is 1.9

Ooo thanks i forgot that

 

[HongYue]

http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_s12_qp_12.pdf
Question 18, 28

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s12_qp_11.pdf
Question 11, 12,

Need Help PLz !!!!

 

[Bluejeans#]

dis ques please

 

[talha-_-khan]

View attachment 28795
dis ques please

1 cm = 6 ms ( milli second )
they are asking time interval and we can see that distance - 4.5 and as we know 1 cm = 6ms so time interval will be 4.5 x 6 =27

 

[talha-_-khan]

how to do this

 

[Bluejeans#]

1 cm = 6 ms ( milli second )
they are asking time interval and we can see that distance - 4.5 and as we know 1 cm = 6ms so time interval will be 4.5 x 6 =27

thanks that was easy ^_^

 

[Bluejeans#]

dis one

 

[talha-_-khan]

dis oneView attachment 28796

0.5 x force x extension = 0.5 x 17 x ( 30 x 10^-2 )

CAN U PLZ ANSWER THIS

 

[Getreal]

In Nov 02 , q 32 , I got that the R at +1V would be 20 , but shouldn't the R at -1V be zero it's only a straight line and I think that downward straight line (infinite) is at -1.5V !!??

 

[Getreal]

L

0.5 x force x extension = 0.5 x 17 x ( 30 x 10^-2 )

CAN U PLZ ANSWER THIS

Lets assume that XY is d , then we take the momentum in the clockwise and anti-clockwise directions which must be equal since the rod is in equilibrium . So , Fsin(30) * d = 10 * d/2 ,
F= 5 / sin(30) = 10 .
It's C then .

 

[Getreal]

dis oneView attachment 28796

Just divide the area under the graph into two trapeziums and the sum of their areas = the strain energy .
* Bear in your mind the units ( cm > m for the extension ).

 

[Bluejeans#]

0.5 x force x extension = 0.5 x 17 x ( 30 x 10^-2 )

CAN U PLZ ANSWER THIS

sorry my battery died :/

 

[Bluejeans#]

Just divide the area under the graph into two trapeziums and the sum of their areas = the strain energy .
* Bear in your mind the units ( cm > m for the extension ).

dis method is a lengthy one :/ n wat abt the unit ?

 

[Bluejeans#]

0.5 x force x extension = 0.5 x 17 x ( 30 x 10^-2 )

CAN U PLZ ANSWER THIS

n btw acoording to wat calculations u did the answer is B ...bt in marking scheme its A :/

 

[talha-_-khan]

 

[khoshi]

L
Lets assume that XY is d , then we take the momentum in the clockwise and anti-clockwise directions which must be equal since the rod is in equilibrium . So , Fsin(30) * d = 10 * d/2 ,
F= 5 / sin(30) = 10 .
It's C then .

which paper??