As physics p1 MCQS YEARLY ONLY.

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kk1997

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please can somebody provide something like this for chemistry Paper 1
thanks in advance
 
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Hanona

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the feather is undergoing free fall , hence a=g and u=0 since it falls from rest. it took T to travel a distance L .. equating in s=ut+1/2at^2 becomes L=0.5x9.8T^2... Now the distance travelled in time 0.5T would be X=0.5x9.8x(0.5T)^2 ... hence the distance as a ratio L would be as follows (0.5x9.8x(0.5T)^2/ (0.5x9.8T^2) = 0.25 of L. therefore the anser is B :) hope it helps...
Hadi Naqvi said:
can you help me with mcq no 8? please:)
9702/12/m/j/11
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IGCSE O/L student

IGCSE O/L student

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Zepudee said:
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w09_qp_12.pdf

Q8,9,13,18,26,27! Help!! :(
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Q8 the total momentum in A adds up to mu, which shows that momentum is conserved.
Q9 force=rate of change of momentum
60=-(30v-30*3)/0.5 <i put a minus sign before the bracket because the force is a retarding force, so the acceleration will be negative>
v= 2
Q13 let's say the initial velocity is 1. when it reaches its highest point, it will only have it's horizontal component of the velocity.
so initially: 1/2 mv^2 = E
later: 1/2 m(v cos(45))^2 = 1/4 mv^2
which is 1/2 E

Q 18 p=hdg
15200 = 0.8*d*9.81
d = 1936

Q 26 they're asking the field strength for q, so we have to take F/q

Q 27 the charged particle is in equilibrium which means, the upward force = downward force
the downward force is it's weight, and the upward force is due to the electric force
so it's a negative charge
charge (Q) = F/E
and the mass is = W/g
the F(electric force) and W are equal
So charge/mass = (F/E)/(W/g)
F & W get cancelled, so the ratio is g/E

Hope you benefitted from my explanation :)
 
Hadi Murtaza

Hadi Murtaza

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