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Do we have to use a black pen or is it ok to use a blue pen?? anyone??
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So sin(pi/3) is root 3 by 2 and why did u write sin (2pi/3) as root 3 by 2?Remember: Sin(2π/3) = Sin(π − π/3) = Sin(π/3) = √3/2
Area = (½) * a * b * SinC
Area = ½ * 6 * 6 * Sin(2π/3)
Area = 36/2 * √3/2
Area = (36√3)/4
Area = 9√3
I wrote with a blue pen in C1 and M1, so am I getting a U ??? :/ Non of the invigilators told us to write with a black pen![]()
i wrote blue in chemistry unit 3,,,so is it considered as a U???
I think its dark enough to be seen on their scanned version.what do you mean dark enough? dark enough to be seen as like black color? or dark enough to be seen by blue?
Hmm, I guess. Geometric sequences annoy me cuz they're so wordy. and then I mess them up. But trig's alright if you know the two main identities. It just takes a little while to figure outNaah man, geometric sequences is simple. Trigonometric identity and equations i much more confusing
Both r equal to √3/2So sin(pi/3) is root 3 by 2 and why did u write sin (2pi/3) as root 3 by 2?
the line 4x-3y-40=0 touches the circle (x-2)^2+(y-6)^2=100 at P(10,0).show that the radius P is perpendicular to the line.
anyone explain this,i seem to confuse here alot,and i hate this chapter :/
Okay guys this might help but not much!please find me some![]()
well first find the area of triange L N N'
so x cordinate of N - x cordinate of L *4 = area of the triangle
then u gotta deduct the area under the graph from M to N ( x cordinate)
so integerate the graph from M to N ( x- coordinate) and then deduct this value from the value of area of triangle
good luck
Which part ??Guys i need help!! in jan 2011 q:9 which two points should we use??
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