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C2 questions - a thread for the purpose of discussion

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If anyone is facing difficulties in solving any C2 past paper, post your questions along with their priority status here - so that I know how long I can take in getting back to you.
Good luck, study hard!
 
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If anyone is facing difficulties in solving any C2 past paper, post your questions along with their priority status here - so that I know how long I can take in getting back to you.
Good luck, study hard!


can you solve a Q for me? ummm its from june 2005 C2 Q no: 4 b)
 
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I have attached a photo which shows how I solved it.
If you find the working to be intangible or still have a question, do feel free to ask.DSC_0099.JPG
 
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man check this .. i have no idea how the hell is it solved
log3(x-2) = -1 ??
 
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shit ya !! its that simple !! =O nd i havent figured it out !! am so gonna fail in tom mock !!

very thankful man ! =)

No problem, just glad to have helped out.
Good luck with your mock tomorrow, I'm sure you'll do fine!
 
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This is a question I thoroughly enjoyed solving.
It's really quite simple once you understand but until then, it's a downright bummer.
This is strictly the working, if you don't get it, tell me which part and I'll get back to you.
DSC_0103.JPG
 
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This is a question I thoroughly enjoyed solving.
It's really quite simple once you understand but until then, it's a downright bummer.
This is strictly the working, if you don't get it, tell me which part and I'll get back to you.
View attachment 6828
but man where the triangle from ???
-.-
nd sin is o/h
 
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MAN !! wake uppp !!!
i got the triangle .. but the sine thin ?? it shoud b opposit over hypotonis ???
nd after we get that how do we find the area of the circle !!
 
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This is how you get the triangle.
First divide the sector into two equal halves so Pie/3 becomes Pie/6
One side (the base) is the radius, r and the other side is 6-r.
In triangle COX, angle X is 90 degrees.
Check the figure of the sector.
OB is tangent to the circle C.
Radius is at right angles to the tangent.
Hence, trigonometry can be applied.
DSC_0001.JPG
 
Messages
940
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1,024
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103
This is how you get the triangle.
First divide the sector into two equal halves so Pie/3 becomes Pie/6
One side (the base) is the radius, r and the other side is 6-r.
In triangle COX, angle X is 90 degrees.
Check the figure of the sector.
OB is tangent to the circle C.
Radius is at right angles to the tangent.
Hence, trigonometry can be applied.
View attachment 6830

MAN !! THANK YOU !!! THANK YOUU !! thank you ! =p =)
;)
though amma fail for a sec !
i still do !! lol

;) thx ! =p
 
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