Chem P3 doubt!! help plzzz

[raihan1904]

M/J 2009 p32 Q1 c part v)

 

[Oliveme]

M/J 2009 p32 Q1 c part v)

add the link please.

 

[raihan1904]

http://www.xtremepapers.com/papers/... AS Level/Chemistry (9701)/9701_s09_qp_32.pdf
Q1 c part 5!! plz solve it n upload it asap

 

[Oliveme]

http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_s09_qp_32.pdf
Q1 c part 5!! plz solve it n upload it asap

tell me the titre value. have you performed this practical?

 

[raihan1904]

titre value is 28
c part 1 is 0.000644
part2 is 5e- for rxn1 n 2e- for rxn2
part3 is 0.0061
part4 is 0.0644
part5 ??
hope u will be able to solve this

 

[raihan1904]

ya i performd it

 

[Oliveme]

i'll try but will take some time

 

[raihan1904]

ok hope so u get it!!

 

[Oliveme]

ok hope so u get it!!

c1 x v1 = c2 x v2 -------------> you can use this formula to find the conc. of FB2
0.0644 x (250/1000) = c2 x (42.5/1000) which gives you 0.379 mol dm^-3. note - here I've assumed the diluted volume is 42.50 cm^3. or you can use the formula they've given in the mark scheme -----> total volume (250)/volume diluted (42.50) x 0.0644.

then step 6, we know moles are 0.379 per dm^3, thus use formula moles = mass/Mr. So, 0.379 x Mr (126) = 47.75 g dm^-3.

 

[raihan1904]

c1 x v1 = c2 x v2 -------------> you can use this formula to find the conc. of FB2
0.0644 x (250/1000) = c2 x (42.5/1000) which gives you 0.379 mol dm^-3. note - here I've assumed the diluted volume is 42.50 cm^3. or you can use the formula they've given in the mark scheme -----> total volume (250)/volume diluted (42.50) x 0.0644.

then step 6, we know moles are 0.379 per dm^3, thus use formula moles = mass/Mr. So, 0.379 x Mr (126) = 47.75 g dm^-3.

tnx veryyyyy much!! god bless u

 

[Oliveme]

tnx veryyyyy much!! god bless u

No need to thank me, thank Allah. And pray for me.

 

[raihan1904]

Inshallah u will get wat u want