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90, 120 and 180.The angles of PCl5 were 90 and 180 I think
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90, 120 and 180.The angles of PCl5 were 90 and 180 I think
its 117-120 in the mark scheme.Shouldnt ethane be a little less than 120 because of the double bond? I write 118...will they mark that correct? Also I wrote triOgonal bipyramidal...will I be penalized for that?
Shouldnt ethane be a little less than 120 because of the double bond? I write 118...will they mark that correct? Also I wrote triOgonal bipyramidal...will I be penalized for that?
X is equal to 2. I guess a bunch of people messed up the bond angles. Did you all know about PCl5?
ap nay 6 kaha se nikala e?6 tha![]()
I think there will be many correct answers for this one.I wrote 2,3-dimethylebut-2-ene for q
Isn't hexene correctSo my answer don't match your's :/
I simply wrote hexene![]()
ThanksHey
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Where did you get the mark scheme from ? of This paper . kindly please give me the link to itits 117-120 in the mark scheme.
2,3 Di-Methyl But-2-ene is also correct imo.As per I think... Organic solution...![]()
51 and 49I attempted it, following the correct method but then screwed up somewhere. I got around 92 and 7% lol. After some Googling, I found out it should be almost 50-50.
2,3 Di-Methyl But-2-ene is also correct imo.
Since 2 moles of the SAME ketone are forming i.e Propanone/ 1 -one
no. of moles didnt change the composition of the compound, its still one organic copmpoundMay be.. I don't know.. They said ONLY 1 Organic product![]()
About the organic question saying ONLY ONE ORGANIC PRODUCT WAS FORMED, the confusion is whether the question meant:
1. Only ONE in quantity
OR
2. ONE TYPE of organic product. May be more than 1 in quantity.
I understood it as 1.
I asked my Chemistry Sir and He said ‘2-methyl pentene’ is correct…About the organic question saying ONLY ONE ORGANIC PRODUCT WAS FORMED, the confusion is whether the question meant:
1. Only ONE in quantity
OR
2. ONE TYPE of organic product. May be more than 1 in quantity.
I understood it as 1.
3 I thinkwhat were the marks for the last question's last part? where we had to draw cis-trans isomers?
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