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Chemistry and Physics some Keypoints/Notepoints (onDemandOnly) !! :)

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Reactions for the formation of acid rain [Including nitrogen oxide as catalyst and how is it regenerated]
 
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For part a(iii)
In first left hand electrode..the reaction is
H2(g) + 2OH–(aq) -> 2H2O(l) + 2e–
so increasing OH- will favour forward reaction, therefore more electrons, thus more negative

IN the second reaction
O2(g) + 2H2O(l) + 4e– -> 4OH–(aq)
increasing OH- favour backward reaction, therefore more electrons, more negative.
 
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For part a(iii)
In first left hand electrode..the reaction is
H2(g) + 2OH–(aq) -> 2H2O(l) + 2e–
so increasing OH- will favour forward reaction, therefore more electrons, thus more negative

IN the second reaction
O2(g) + 2H2O(l) + 4e– -> 4OH–(aq)
increasing OH- favour backward reaction, therefore more electrons, more negative.
thnk bro can u explain fr part b also..??
nd yeh one thing I missed
so3 + h2o gives h2so4 which makwd acid rain
 
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thnk bro can u explain fr part b also..??
nd yeh one thing I missed
so3 + h2o gives h2so4 which makwd acid rain
Okay see, from the equation of the booklet
Thank you so much!! Jazaka Allah khairan.

Pb2+ + 2e– ⇌ Pb E=–0.13
PbO2 + 4H+ + 2e– ⇌ Pb2+ + 2H2O E=+1.47

So when Pb2+ decrease
the 1st reaction will go backward..making it more negative
while 2nd reaction will go more forward so more positive

So the difference between the two number will increase.
 
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Assalamu 'Alaykum.
Can somebody please post the link to the winter 2011 examiner's report please?
Jazakum Allahu Khair..
 
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can any one tell me how to draw the sructural formulae of june 11 paper 41 ques 6 part (b) strucure D?
 
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