Chemistry can someone explain that

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Tin has reduced Silver Sn + Ag+ --> Ag + Sn2+

Always balance the charge ( theres 1 charge on right and 2 on the left ) so to balance the charge u multiply Ag+ by 2 so that charge on the left is 2 and charge on the right is 2..... And then Tin has lost electrons so it has been oxidised so Sn --> Sn2+ is oxidation
 
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Tin has reduced Silver Sn + Ag+ --> Ag + Sn2+

Always balance the charge ( theres 1 charge on right and 2 on the left ) so to balance the charge u multiply Ag+ by 2 so that charge on the left is 2 and charge on the right is 2..... And then Tin has lost electrons so it has been oxidised so Sn --> Sn2+ is oxidation
Really thanks i got it now
 
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