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no problem, that was really helpfulAnonymousx3 said:xHazeMx said:check 5 & 6 there is one extra hydrogen atom, thx anywaysAnonymousx3 said:The 7 isomers of C3H4Cl2 :
1. CH3CH=CCl2
2 & 3. CH3Cl=CHCl (this has a -cis and a -trans form)
4. CH2ClCCl=CH2
5 & 6. CH2Cl=CHCl (this also has a -cis and a -trans form)
7. CHCl2CH=CH2
I hope that made sense.![]()
Oops, I typed it wrong.
CH2ClCH=CHCl
it's B right ?ideggkr said:Can anyone answer this?
xHazeMx said:it's B right ?ideggkr said:Can anyone answer this?
xHazeMx said:answer this giving an explanation for ur answer
Anonymousx3 said:xHazeMx said:it's B right ?ideggkr said:Can anyone answer this?
Please can you explain why?
xHazeMx said:answer this giving an explanation for ur answer
sorry had to go. anyways zishi answered uAnonymousx3 said:xHazeMx said:it's B right ?ideggkr said:Can anyone answer this?
Please can you explain why?
xHazeMx said:answer with an explanation
xHazeMx said:answer with an explanation
how the oxidation number of Ag remains the same? what will be the oxidation number of the (S2O3)2 part ???Zishi said:xHazeMx said:answer with an explanation
A, by eliminating the other options. The oxidation states of all the atoms remains same.
xHazeMx said:how the oxidation number of Ag remains the same? what will be the oxidation number of the (S2O3)2 part ???Zishi said:xHazeMx said:answer with an explanation
A, by eliminating the other options. The oxidation states of all the atoms remains same.
xHazeMx said:explanation
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