Chemistry MCQ'S help

[roadtrip9o9]

ive been trying to get my doubts cleared but it isnt working on the main 'AS CHEM POST YOUR DOUBTS HERE' and as exams are on 9th may i had to post a new thread for em ... so i would be really greatful if someone cleared these...http://www.xtremepapers.com/papers/...d AS Level/Chemistry (9701)/9701_s09_qp_1.pdf Doubt in 11,13,16,22,23,26,28,29,30,32,40 ....... .......... http://www.xtremepapers.com/papers/... AS Level/Chemistry (9701)/9701_w09_qp_12.pdf 3,4,6,8,10,15,18,21,22,23,25,,26,27,28,35,40 ............................ Thanks

 

[roadtrip9o9]

http://www.xtremepapers.com/papers/... AS Level/Chemistry (9701)/9701_s10_qp_12.pdf 3,9,10,12,14,16,21,25,26,27,29

 

[xxfarhaxx]

http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_s10_qp_12.pdf 3,9,10,12,14,16,21,25,26,27,29

3. IE increases across da period so its A
9. ANS: D
student P is wrong cz the pH of X is 6, which is almost neutral , thrfr its nt a strong acid..nly option is D.
14. A-coz a salt is produce NaSO4 n H2O..

 

[aaaamfa]

Guys need help in the following question
Chemistry as level june 2012 variant 11
Question number 9. I dont where to start from
So need help asap

 

[shazmina]

Guys need help in the following question
Chemistry as level june 2012 variant 11
Question number 9. I dont where to start from
So need help asap

do u still have them as a doubt?????? caz if not cleared then i can help u

 

[aaaamfa]

do u still have them as a doubt?????? caz if not cleared then i can help u

No not at all i understood them but if u want i will post more cuz i have many

Thanks

 

[saniyaaamir]

Can somebody please explain how is the answer c?

 

[Silverglitter]

Can somebody please explain how is the answer c?[/quote)
The first or the second question?

 

[sudeep1097]

Can someone help me with 2010 m/j 12 question number 5 and 21 and explain also! Thank you!

 

[Faaiz Haque]

Can someone help me with 2010 m/j 12 question number 5 and 21 and explain also! Thank you!

For question 5 -214+38 = -176
We add them because I2(G) is used in the original equation not solid.

Then since 2 moles of ICl3 are produced you do -176/2 = -88kj/mol-1