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yaaa that helped..!! A LOOT!!its a nucleophilic substitution bcoz d C atom bonded to the hydroxyl grp will carry a partially positive charge (diff in electronegativity of O n C).
This makes it open to nucleophilic attack. ie the partially -ve halogen atom in hydrogen halide will attack the bond btw the C n hydroxyl grp..
Hope i helped!!
)
For Question 11 you can see that the equilibrium concentration of Z decreases as the temperature is increased. This means that increasing the temperature lowers the forward reaction (or more simply the Kc for the reaction), and you must remember that Kc for exothermic reaction decreases with increasing temperature (because exothermic gives out heat energy)Anyone explain these two questions to me please? Thanks first! :Yahoo!:
FYI, the answer given for Q10 is D whereas for Q11 is D.
yaaa that helped..!! A LOOT!!
(i kinda tend to miss the most obvious stuff..!!
thnx once again
For 8, find the mass of Cl2 ie 5.287 - 2.920 = 2.367g
the greater the ph value the weaker the acid..rit?
Ya noww i get it. well you know you asked this one at school and you drew the whole thing. only problem was i didnt think there would be any other double bond in the chain but only in the cyclohexene ring. But it was supposed to be the opposite. well thanks.Did it for you (sorry, diagram doesn't really look good)
Then
Defend nhin kr rhihan han.. kar lo defend apnay aap ko...
..
han han... sixth sense achi hai kaafi aapki... paper ki guesses bnaya karo beth k...Defend nhin kr rhi
mujhey pata tha k aap ko yehi lagey ga
profit...)
Q3- total mr of P2O5= (31*2)+(16*5)
Bs kya karienhan han... sixth sense achi hai kaafi aapki... paper ki guesses bnaya karo beth k...
A ketone doesn't change the color of potassium dichromate (because it can't be further oxidized), so it can't be A.For question 2, 2 double bonds in he compound were removed, thus 4 mole of hydrogen was required (since 2 hydrogens are added to the chain once you break a double bond). If you notice, CH2 was changed to CH3 thus one more mole os Hydrogen was required. So in total, 5 mole of hydrogen was required.
Question 3, first of all find the Mr of P2O5, which is (31*2)+(16*5)= 142.
Now find the amount of phosphorus present in this amount, which is (31*2)/142= 0.4366...
The question said, only 30% of it dissolves, so 0.4366*30= 13.09, which is almost equal to 13.1, hence answer is B.
Question 4-
Ethanol will not react with NaOH. Since a hydroxyl group is present in both of them, no nucleophilic substitution will happen, so it has to be ethanoic acid.
Question 5-
This question is hell tricky, and I've been trying this for half an hour now, and I don't see how to differentiate between A and D, both of 1 mol of A and D, will require 2 mol of HCN, and both will change the color of potassium dichromate.
I will try to brain storm this question with one of my friends, and she might come up with something.
Till then I'll be grateful if someone can reason out why it should be D, not A, please?
Here's the question:
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