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how do I know the half equations are that way?19. Divide the equation into half equations, the oxidation half and reduction half:
Oxidation half:
1/2Cl2 + 6OH- -------> ClO3 - + 3H2O + 5e
Reduction Half:
(Cl2 + e ------> Cl- ) * 5
1/2Cl2 + 6OH- ------> ClO3 + 3H20 + 5e
5/2Cl2 + 5e -------> 5Cl-
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3Cl2 + 6OH- -------------> 5Cl- + ClO3 + 3H20
So the answer is C.