computer studies questions

[harshkaullychurn]

hello sir/madam,

can i get some tips or expected questions on computer studies which is on thursday 28 october.

 

[Shahnam]

get yourself well practised with the flow charts and algorithms.

 

[harshkaullychurn]

ok fnxX

 

[Heshna]

Any hints for the types of questions we might get.....????

 

[harshkaullychurn]

i think you must work all the papers as cambridge has no more new questions.work especially june 2006 and 2007.

 

[Heshna]

thanks...!!!

 

[mimmi]

Guys! Whats the code in algorithm to arrange a set of numbers in ascending or descending? i know there is an easier way than writing 100's of line which will make the examiner :evil:

 

[salsabeel]

revise well on how to create an expert system and how to use an expert system... also dnt forget proces control..

 

[Heshna]

d0nt forget to revise on trace tables and system flowcharts...these types of questions are recurring..!!

 

[harshkaullychurn]

@mimmi
hi,culd u tell me wat's zat easier way please?????

 

[axhynic]

Guys! Whats the code in algorithm to arrange a set of numbers in ascending or descending? i know there is an easier way than writing 100's of line which will make the examiner :evil:

Input A,B,C,D
If A>B then
T=B
B=A
A=T
Endif
If A>C then
T=C
C=A
A=T
Endif
If A>D then
T=D
D=A
A=T
Endif
If B>C then
T=C
C=B
B=T
Endif
If B>D then
T=D
D=B
B=T
Endif
If C>D then
T=D
D=C
C=T
Endif
Output A,B,C,D

Thats for acceding order, i think

 

[mimmi]

Azheen!! O_O

What if it's a 1000 numbers >_>

And what's the code for making the program wait for let's say 24hrs?

 

[bamteck]

Yea work exam papers for the year 2005, 2006, 2007 !
Remember the answers !
U might get a distinction!

 

[axhynic]

Azheen!! O_O

What if it's a 1000 numbers >_>

And what's the code for making the program wait for let's say 24hrs?

for 1000 numbers, array concept should be used. i don't know how
and i once used 'timer=x' at school but cant recall how it was done...

 

[examman]

Guys! Whats the code in algorithm to arrange a set of numbers in ascending or descending? i know there is an easier way than writing 100's of line which will make the examiner :evil:

Input A,B,C,D
If A>B then
T=B
B=A
A=T
Endif
If A>C then
T=C
C=A
A=T
Endif
If A>D then
T=D
D=A
A=T
Endif
If B>C then
T=C
C=B
B=T
Endif
If B>D then
T=D
D=B
B=T
Endif
If C>D then
T=D
D=C
C=T
Endif
Output A,B,C,D

Thats for acceding order, i think

try putting loops ... btw, it wont come for 1000 numbers

loops such as
For Counter,
While Do, And
Repeat UNTIL

Use the forcounter its the easiest.... for instance to find the total number of negeative numbers in 1000 numbers below is the algorithim

Neg = 0
For Counter = 1 to 1000
Input Number
If Number < 0 THEN
Neg = Neg + 1
Next Counter.
Output Neg.

then ask me anything regarding algorithms
btw, im doing my olevel next year im in year 9 xD

 

[mimmi]

It was an easy algorithm =P

 

[bamteck]

It was a decent paper ! Isn't it?

 

[axhynic]

try putting loops ... btw, it wont come for 1000 numbers

loops such as
For Counter,
While Do, And
Repeat UNTIL

Use the forcounter its the easiest.... for instance to find the total number of negeative numbers in 1000 numbers below is the algorithim

Neg = 0
For Counter = 1 to 1000
Input Number
If Number < 0 THEN
Neg = Neg + 1
Next Counter.
Output Neg.

then ask me anything regarding algorithms
btw, im doing my olevel next year im in year 9 xD

could you try using a for counter, while do or repeat until to input 4 numbers and output them in descending order?

It was a decent paper ! Isn't it?

i lost myself at question 19 :x
the algorithm was a piece of cake but overall, a decent paper

 

[mimmi]

Question 19?

i only had problem with 1 mark! everything else IS CORRECT lol

 

[iFuz]

Guys! Whats the code in algorithm to arrange a set of numbers in ascending or descending? i know there is an easier way than writing 100's of line which will make the examiner :evil:

for next statement is best 1
eg print even nos in desc order from 100 to 1
1 start
2 for a= 100 to 1 step -2
3 print a
4 next a
5 end...
as simple as that