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ECAT and MCAT Preparation: Post your doubts here!

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The equation for finding the energy levels in any atom is given by the equation:
E= -13.6((Z^2)/(n^2)), where the energy is in electron volts, Z is the number of protons, and n is the energy level you want to find the value for.
 
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2nd Law of t.d

Kelvin Statement : we cannot get continuous work without expenditure of energy. Cold Body is necessary to transfer heat or to make a heat engine

Clausius statement : we can not transfer heat from cold body to hot body without expenditure of energy (as in Refrigerator)

i would suggest , just study every topic as briefly as possible ,dont get into unnecessary details
 
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2nd Law of t.d

Kelvin Statement : we cannot get continuous work without expenditure of energy. Cold Body is necessary to transfer heat or to make a heat engine

Clausius statement : we can not transfer heat from cold body to hot body without expenditure of energy (as in Refrigerator)

i would suggest , just study every topic as briefly as possible ,dont get into unnecessary details
means video i posted is correct!
 
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Ok here is a question 4 u all, i know the ans but u all should try

I have to through the ball with a certain constant velocity so with what angle should i through it, so that i could cover same vertical and horizontal distance.....
 
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U all should know that sum of all the complex roots of a number is always 0(zero) means 1+w+2 = 0 and x^2 = 4 so
x = +2 or x = -2
2-2 =0 or x^3 = 5^3 so
x = 5,5w,5w^2
sum of them is zero
same would be for
roots of
X^7 = 7

and so on
sum of roots should be zero whether there are two roots or hundred roots
 
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Come on , common sense is something, i m asking question from students of A2 , it would not be that simple...
Moreover , add the fact that its projectile motion or (the ball should cover some horizontal distance too
and there are people who call others kiddo..:D
Slash (y)
 
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if the total score of the 12 student class is x then x/12=70 and x=70×12=840
similarly if the total test score of the 18 student class is y then y18=80 so y=18×80=1440
the total combined is 1440+840=2280 so the average over the 30 students is 2280/30=76
oh thanx alot really very nice... bro. :):):):)(y)
 
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Ok here is a question 4 u all, i know the ans but u all should try

I have to through the ball with a certain constant velocity so with what angle should i through it, so that i could cover same vertical and horizontal distance.....
76 degrees?



http://www.pieas.edu.pk/admissions2012/Sample_Test_Paper_BS.pdf
physics 57 is D rite???

and how to deal with 58 ??? next one??
a prper working fr this one wil be awsome
thanx

and question 70) is again D rite???

and question 75 B is the ans????
57 yeah i think d
58: i remember this formula {temp. in Celsius - 0}/100 = {temp. in Fahrenheit - 32}/180
In this 0 and 32 are the lower fixed points in both the scales respectively, 180 is the number of divisions on the Fahrenheit scale and 100 is the number of divisions o the Celsius scale.
You can take 100 and 212 instead of 0 and 32 as well
so you have: [450-0]/100 = 4.5 * 180 = 810 + 32 = 842

70 and 75 i think both are D :unsure:
 
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76 degrees?




57 yeah i think d
58: i remember this formula {temp. in Celsius - 0}/100 = {temp. in Fahrenheit - 32}/180
In this 0 and 32 are the lower fixed points in both the scales respectively, 180 is the number of divisions on the Fahrenheit scale and 100 is the number of divisions o the Celsius scale.
You can take 100 and 212 instead of 0 and 32 as well
so you have: [450-0]/100 = 4.5 * 180 = 810 + 32 = 842

70 and 75 i think both are D :unsure:
76 degrees?




57 yeah i think d
58: i remember this formula {temp. in Celsius - 0}/100 = {temp. in Fahrenheit - 32}/180
In this 0 and 32 are the lower fixed points in both the scales respectively, 180 is the number of divisions on the Fahrenheit scale and 100 is the number of divisions o the Celsius scale.
You can take 100 and 212 instead of 0 and 32 as well
so you have: [450-0]/100 = 4.5 * 180 = 810 + 32 = 842

70 and 75 i think both are D :unsure:



can u explain he reason behind ur ans to be D fr 75:unsure:
 
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