expected grade boundries for As math p12

[Muhammad Arham Ayaz Malik]

Lol bro these 2 are diff questions
tangent one was q9 and the vector one was different

 

[Muhammad Arham Ayaz Malik]

Tell me the exact question and I will tell you the correct answer if I remember it

 

[Snowysangel]

Lol bro these 2 are diff questions
tangent one was q9 and the vector one was different

I know and I got my mistake. I forgot multiply by -1 when differentiating...so I got the equation of the tangent wrong too (i got -.5 + x wheh it was +.5 + x) and so i got the area wrong too. Is there ecf in p1?

 

[Snowysangel]

Tell me the exact question and I will tell you the correct answer if I remember it

The tangent one

 

[Muhammad Arham Ayaz Malik]

Oh , your bad luck
I dont think there is an ecf but even if it is not u still can score an A if only your q9 was wrong , cheers !

 

[Muhammad Arham Ayaz Malik]

And one thing more the value of p was 2 not -4 :/ in that psintheta=1 question

 

[Snowysangel]

Oh , your bad luck
I dont think there is an ecf but even if it is not u still can score an A if only your q9 was wrong , cheers !

Will they give me 1/2 in the equation of the tangent part? Cause I used the right method of plugging in the value

 

[Snowysangel]

And one thing more the value of p was 2 not -4 :/ in that psintheta=1 question

There were 2 p's in the exam..

 

[Muhammad Arham Ayaz Malik]

Hope so, but one thing , ecf wont be there because the line was clearly shown on diagram with a positive gradient
If it was another +vs value it would have made sense for ecf but this not

 

[Muhammad Arham Ayaz Malik]

Which one was the other than this p ?

 

[Snowysangel]

Hope so, but one thing , ecf wont be there because the line was clearly shown on diagram with a positive gradient
If it was another +vs value it would have made sense for ecf but this not

I tried to make it positive but I forget all about the -x...although I didn't while I reheating for some reason.. But it is a really really minor mistake :/ the second p was what you remember as k

 

[Snowysangel]

*integrating

 

[thementor]

Q1. (3.5,0)
Q3. -145 is the coefficienr
Q4(a) p=2,(b)perimeter was 34.1
Q5.(b) theta=116.6, 296.6
Q6(a) r=1.5
Q7 was vectors.
Q8.(-2,10.83) this question was checked using an online graph calculator so it is absolutely correct
in Q9 was 0.583
Q10 value of p was -4

 

[Muhammad Arham Ayaz Malik]

Oh yes that range was -4 !

 

[Muhammad Arham Ayaz Malik]

Wo

Q1. (3.5,0)
Q3. -145 is the coefficienr
Q4(a) p=2,(b)perimeter was 34.1
Q5.(b) theta=116.6, 296.6
Q6(a) r=1.5
Q7 was vectors.
Q8.(-2,10.83) this question was checked using an online graph calculator so it is absolutely correct
in Q9 was 0.583
Q10 value of p was -4

Wow ! Can u tell q7 and q2 answers plz

 

[Muhammad Arham Ayaz Malik]

*integrating

Can you tell me the exact p question of the last one
I am not remembering it , though I know one of my answer was -4

 

[Snowysangel]

Q1. (3.5,0)
Q3. -145 is the coefficienr
Q4(a) p=2,(b)perimeter was 34.1
Q5.(b) theta=116.6, 296.6
Q6(a) r=1.5
Q7 was vectors.
Q8.(-2,10.83) this question was checked using an online graph calculator so it is absolutely correct
in Q9 was 0.583
Q10 value of p was -4

Wasnt q8 (-2,14 1/3)

 

[thementor]

yes Q2 (I)(a) was sin p= -sqrt(1-k^2)
and tan p was -(sqrr(1-k^2))/p
and sin2theta will be negative becoz sin theta will be negative and cos will be positve so sin times cos will always give a negative answer. This question could have been done very easily by those who have studied p3

 

[Snowysangel]

Can you tell me the exact p question of the last one
I am not remembering it , though I know one of my answer was -4

There was this equation 4x2-4x + something and it was equal to p. we had to find the valueof p for which there were two equal and distinct roots

 

[Muhammad Arham Ayaz Malik]

I have the same answers as this guy