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A is the point with coordinates (2,8)and B is the point with coordinates (14,4). A straight line L is perpendicular to line AB and passes through A. Find the equation of the straight line L.
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First find the gradient of ABA is the point with coordinates (2,8)and B is the point with coordinates (14,4). A straight line L is perpendicular to line AB and passes through A. Find the equation of the straight line L.
Thanks!First find the gradient of AB
A (2,8) B (14,4)
gradient = (4 - 8) / (14 - 2)
= -4 / 12
= -1/ 3
Gradient of perpendicular AB = 3
Since it passes through A
( y - 8)/(x - 2) = 3
y - 8 = 3x - 6
y = 3x + 2
WelcomeeThanks!
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