Yep.Can you check out the PM?
This is Q4:
I'll start Q5 now
***** EDIT *****
In the last row of formulae I accidentally wrote 8n, I meant to write 7n
We are currently struggling to cover the operational costs of Xtremepapers, as a result we might have to shut this website down. Please donate if we have helped you and help make a difference in other students' lives!
Click here to Donate Now (View Announcement)
Yep.Can you check out the PM?
Q5Can you check out the PM?
what if u get a - value?Q5
Remember to learn the more important polar graphs. It saves you a lot of trouble
Treat it as if it were the angle being negative, not the 'r' valuewhat if u get a - value?
I think you should try it yourself, see what happens!Can you draw and a send a pic of that same curve from 0 to pi?
I drew it but im not sure about the shape.I think you should try it yourself, see what happens!
I also can't be bothered hahahah
Give me 30 mins I gotta do a couple things and then I'll get to itCan someone show me the steps for 2011 N P13 Q2. Help is appreciated. Thanks in advance!
It's ok. I got it already.Give me 30 mins I gotta do a couple things and then I'll get to it
Alright, it's solved, let me send you the full solutionIt's ok. I got it already.
I do need help with 2012 N P13 tho.
Q12 OR, I'm not sure how to show the last part.
It's ok. I got it already.
I do need help with 2012 N P13 tho.
Q12 OR, I'm not sure how to show the last part.
Are we all ready for Monday?
Product of roots of a quartic equation.Need help with 9231/11/MJ/14 Q7 second part "Deduce...". THANKSS.
Are you talking about the part to deduce the roots of equation are.... ?Product of roots of a quartic equation.
Then explain that the positive root is taken as both tan pi/5 and tan2pi/5 are positive.
Basically equate tan 5theta to 0, and reject any values than gives tan theta = 0 (0) as it is not the solution of the eqn intended.Are you talking about the part to deduce the roots of equation are.... ?
I know how to solve the last part 'Hence show that...' But not the 'deduce...'
I'm sorry I still don't get it. Could you explain further?
Oh I get it now! Wasn't that complicated after all.Basically equate tan 5theta to 0, and reject any values than gives tan theta = 0 (0) as it is not the solution of the eqn intended.
Then find theta that with limits of (-pi, pi)
For almost 10 years, the site XtremePapers has been trying very hard to serve its users.
However, we are now struggling to cover its operational costs due to unforeseen circumstances. If we helped you in any way, kindly contribute and be the part of this effort. No act of kindness, no matter how small, is ever wasted.
Click here to Donate Now