Get ready for Chemistry...!!!

[Wâlèé Atèéq]

All question...!! discuss here..!!
I want to knw if there r 4 ions in a solution..!! how to identify the ion is going to be a gas..?

 

[crosspoint23]

Guys, i really have hard time in understanding electrolysis. can anyone explain or tell me the important things in electrolysis?

 

[Wâlèé Atèéq]

Guys, i really have hard time in understanding electrolysis. can anyone explain or tell me the important things in electrolysis?

Same here..!! is there anything..!!

 

[mooncity]

in electrolysis ? ik how to

 

[mooncity]

for that you should first know are the electrodes inert or reactive and you have to learn reactivity series too

 

[crosspoint23]

I only know the reactivity series

 

[mooncity]

I only know the reactivity series

ok good so in a solution there are always 4 ions 2 of which solution u re using and 2 of water H and OH and if you know the reactivity series and always the more reactive takes the part at anod and cathode understood ? and if the electrodes are reactive they will also take part... AT CATHODE the positive ions get discharged as an atom and at Anode negative ion get discharged

 

[crosspoint23]

How about writing the half equation?

 

[mooncity]

How about writing the half equation?

half equation u mean
like 2Hplus+2emines--->h2

 

[mooncity]

so always at cathode u gotta write like this only because they gain electrons whether its hydrogen or cu u always have to write in form of e.g" cu2plus+2emines---->cu

 

[crosspoint23]

Ohh ok, how bout anode?

 

[mooncity]

anode is just the opposite of cathode equation and yeah for anode also remember the reactivity of negative so4-,no3-,(co3)2-,OH- and with that Cl-,Br-,I- ok
so if there is OH- and cl- the cl- will go to the anode not oh- remember ok so remember at anode the equation will always in the form of this
for e.g:
4OH------>2H20 + O2 + 4e-
or
2cl- ---->cl2+2e-

 

[mooncity]

Inert electrodes like graphite/platinum
if you are having active electrode like copper electrodes
thn in a solution of
cu2+ So4-
H+ OH-
this at anode cu will discharged not OH bcz cu is reactive electrode

At cathode
cu2+ +2e- ---->Cu
At Anode
cu------> cu2+ + 2e-

 

[mooncity]

and yes also remember that when u re using two ions at electrode and other 2 ions are left behind in solution so according to that the solution become acidic or akaline bcz concentration of reacting ions get decreased and concentration of left behind ions increases