Guys any tips for Maths Paper 42???

[tottybee3]

I

I have a doubt in this paper http://papers.xtremepapers.com/CIE/Cambridge IGCSE/Mathematics (0580)/0580_w12_qp_43.pdf
q5(b)..pls help!!

have the same doubt and I sent u a mail

 

[Akshajistari]

I have a doubt in this paper http://papers.xtremepapers.com/CIE/Cambridge IGCSE/Mathematics (0580)/0580_w12_qp_43.pdf
q5(b)..pls help!!

Firstly, xy=5cm2, therefore y=5/x .
Then, Y(x+2)=6, so Y=6/(x+2).

According to that, y+Y=1 will become (5/x) + (6/(x+2)) = 1.

After that taking the LCM of the fractions, we will get (5x+10+6x)/(x^2 + 2x) =1

Simplifying that, (11x + 10)/(x^2 + 2x) = 1.

Take the denominator over to the other side, making 11x + 10 = x^2 + 2x

Move everything over to the other side: x^2 + 2x - 11x -10 = 0

Upon simplifying, you will finally get x^2 -9x -10 = 0

Hope I helped!

 

[Ameena Eesa]

That person is lying....please look at the profile to get 2 know he or she had asked for tips just minute b4 posting that

poor thing didnt lie......... mustve said something in an anxietous jiffy.........

 

[<><> Ice <><>]

Tip : Solve your paper at maximum potential, because last year, students didn't even get to finish the paper in time :'(

 

[FlameBlazer69]

Call_me_loody here you go, if there's any angle I missed out on, let me know. Hope images are clear .

 

[Ameena Eesa]

I Neeeeeeeeeeeeeeeeeeed heeeeeeeeeeeeeeeeeeeeeeeeeeelp
I don't really know the types of angels, like what is adjacent, corresponding alternative, vertically opposite, or any other, if there is.
MY EXAM IS TOMORROW, ITS URGENT PLEASE!
Thanks in advance

http://www.bbc.co.uk/schools/gcsebitesize/maths/geometry/polygonsrev4.shtml

 

[Ameena Eesa]

Mavilda Bucket

Now find the lengths of the sides, and calculate BC using pytho..............................

 

[FlameBlazer69]

Oh... That's really kind of you, thanks alot!
but.. what about adjacent? is corresponding and adjacent the same thing?

Really sorry I forgot what adjacent is, lemme think gimme a few mins

 

[FlameBlazer69]

Adjacent angles > http://www.mathsisfun.com/geometry/adjacent-angles.html

 

[FlameBlazer69]

Anytime

 

[Ameena Eesa]

Awesome12 plzzzzzzzz help............... part ii

 

[FlameBlazer69]

Ehhh... help? :/

 

[Mavilda Bucket]

View attachment 42059

Awesome12 plzzzzzzzz help............... part ii

cant u use freq density for this?

 

[FlameBlazer69]

cant u use freq density for this?

freq density = freq/class width
try to apply here, it doesn't work :/

 

[Awesome12]

View attachment 42059

Awesome12 plzzzzzzzz help............... part ii

See calculate the frequency density for 60-80
It is 0.7
However on the histogram, they have made it 2.8
thus the ratio is
0.7 : 2.8

For example for the group 120-150
f.d = 32/30
= 1.0667

Thus on the histogram, it will be

0.7 : 2.8
1.0667: x

Cross multiply and find x. Do this for the other values

 

[slisjunknown]

Firstly, xy=5cm2, therefore y=5/x .
Then, Y(x+2)=6, so Y=6/(x+2).

According to that, y+Y=1 will become (5/x) + (6/(x+2)) = 1.

After that taking the LCM of the fractions, we will get (5x+10+6x)/(x^2 + 2x) =1

Simplifying that, (11x + 10)/(x^2 + 2x) = 1.

Take the denominator over to the other side, making 11x + 10 = x^2 + 2x

Move everything over to the other side: x^2 + 2x - 11x -10 = 0

Upon simplifying, you will finally get x^2 -9x -10 = 0

Hope I helped!

Thnx a billion....It did help and I got it

 

[Lavinge]

did u seriously fin d exam??r ru kiddin??

she was probably talking about paper 2?

 

[silver_moon]

she was probably talking about paper 2?

i don think so..coz vryone's ritin in d sam tym...

 

[Awesome12]

Ehhh... help? :/View attachment 42060

5 (a) 27/x, as imagine you have spent $10 on toffees. Each toffee costs $x ( lets say $2). Thus you will have 10/2 = 5 toffees
(b) 25/x-2, as stated above
(c)

 

[Ameena Eesa]

Awesome12 Can you briefly explain how will we do this on the graph? the left part pf the equation is the graph's eqn.