help required 9702_w03_qp_2

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hassam

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we have to draw a graph of v against s....use third eqation....v^2=u^2+2as where u is zero so we get v^2=2as.....now taking sqrt...v=sqrt.(2as)....we can also write it as v=sqrt.(2a)times sqrt.(s)...since acceleration is a constant in this equation we can write it as v=k.sqrt(s).....so its a square root relationship
 
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