help !!

[sibtain1227]

can any 1 explain me Q8 OCT-NOV O2 P1 chemistry
PLZZZ

 

[sibtain1227]

Q9 aswell

 

[sweetiepie]

q11 also..

 

[WellWIshER]

POST LINK PLZ

 

[sibtain1227]

@sweetie pie

at equlibrium H2 and I2 have moles 'X'
X multiplied b X makes X(square)
HI2 at equlibrium would then have (b-X) square as it has 2 moles at equlibrium
thus the expression wud turn out to be as that shown in D

i hope it helped

 

[sweetiepie]

thankss....

 

[sibtain1227]

http://www.xtremepapers.me/CIE/Internat ... 2_qp_1.pdf

 

[sibtain1227]

ur welcum !!

 

[sibtain1227]

q8 and q9 ??

 

[sibtain1227]

hey hey i m sorry i xplained it the wrong way

the question says that at equlibrim X moles of HI had disassociated
so at equlibrium H2 and I2 would have X/2 moles

and HI would have B-X (square)
x/2 multiplied by x/2 makes it x(square)/4

further expansion makes it as that in D

 

[sibtain1227]

as HI and H2 / I2
are in a ratio of 2/1

thus making it x/2

 

[umarashraf]

mcq 9.. its easy.. it involves concept of born hyber cycye... formation of any compound is always a result of its gaseous elements combing together.. first carbon would be atomised then oxygen would be converted from molecule to atom...

 

[sibtain1227]

thanks
wat abt q8

 

[libra94]

hey hey i m sorry i xplained it the wrong way

the question says that at equlibrim X moles of HI had disassociated
so at equlibrium H2 and I2 would have X/2 moles

and HI would have B-X (square)
x/2 multiplied by x/2 makes it x(square)/4

further expansion makes it as that in D

why cant it be A?? why do u multiply by 4?? we just need to square it by 2 only, right? plz explain me this part.
thnks.

 

[sibtain1227]

@libra
the statment says that at equilibrium X moles oh HI dissociate

as HI and I2 or H2 are in a ratio of 2/1
therefore its gives x/2 moles at equilibrium !!

hope u get it

 

[sweetiepie]

ahan okay no prob thankss...