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Hot and Cold =P

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Okaaay this question is about alevel organic chemistry, if u guys were thinking abt something else :lol:


i dont know wht paper this is, but the question is:

Draw the structural formulae of molecules/ ions formed when "CH3CONH - (benzene ring) - OH" reacts with

(i) Br2 (aq)
(ii) NaOH (aq) in the cold
(iii) NaOH (aq) under reflux


Whts the difference b/w (ii) and (iii)? :unknown:
 
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ParanoidAleveler said:
Okaaay this question is about alevel organic chemistry, if u guys were thinking abt something else :lol:


i dont know wht paper this is, but the question is:

Draw the structural formulae of molecules/ ions formed when "CH3CONH - (benzene ring) - OH" reacts with

(i) Br2 (aq)
(ii) NaOH (aq) in the cold
(iii) NaOH (aq) under reflux


Whts the difference b/w (ii) and (iii)? :unknown:

cold means at rtp or under low temp
and reflux means heating for long time
 
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workinghard said:
wait i ll draw dem n upload dem...
is katy perry ur inspiration 4 da title?!:p


yes please do! =)

LOL yea! idk all these random songs keep popping up in my head while i study :fool:
 
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princesszahra said:
ParanoidAleveler said:
Okaaay this question is about alevel organic chemistry, if u guys were thinking abt something else :lol:


i dont know wht paper this is, but the question is:

Draw the structural formulae of molecules/ ions formed when "CH3CONH - (benzene ring) - OH" reacts with

(i) Br2 (aq)
(ii) NaOH (aq) in the cold
(iii) NaOH (aq) under reflux


Whts the difference b/w (ii) and (iii)? :unknown:

cold means at rtp or under low temp
and reflux means heating for long time



but how does the structure of the product differ?
 
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ParanoidAleveler said:
Okaaay this question is about alevel organic chemistry, if u guys were thinking abt something else :lol:


i dont know wht paper this is, but the question is:

Draw the structural formulae of molecules/ ions formed when "CH3CONH - (benzene ring) - OH" reacts with

(i) Br2 (aq)
(ii) NaOH (aq) in the cold
(iii) NaOH (aq) under reflux


Whts the difference b/w (ii) and (iii)? :unknown:
Cold NaOH only dissolves the compound ... OH group on benzene ring reacts with NaOH ... since phenols are acidic in nature...
In Hot NaOH and when heated ... the amide bond breaks because the conditions to break the amide bond are OH-/H+ and heat(under reflux) ... you get CH3COO-Na+ and C6H5O-Na+ ... hope that helps :)
 
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