- Messages
- 6
- Reaction score
- 1
- Points
- 3
FOR QUESTION 2 I JSUT USED AREA UNDER GRAPH, SUVAT WAS NOT NEEDED ON ANY QUESTION ON THE PAPPER!
We are currently struggling to cover the operational costs of Xtremepapers, as a result we might have to shut this website down. Please donate if we have helped you and help make a difference in other students' lives!
Click here to Donate Now (View Announcement)
the vertical component is only balanced by the tension in that rope rite?For the force S, I drew it to the north east direction because weight is more so it needs an upwards component
Bro... i made a mistake in calculating the distance.... like for a certain part while the stone was falling we had to calculate the distance and by mistake i multiplied the time with velocity instead of acceleration...so got the distance to be 23.As a result got the displacement to be 7.66 downwards...... how much mark will I lose?For Q2
Q2 17.2 speed at 3.0s distance was 22.7,displacement 7.33 vertically down
Graph of velocity was a straight line with negative gradient with x intercept at 1.25 and y intercept at 12.2 and on the other side at the end at 3 s it was -17.2
no that's not correct. the question very clearly mentioned "constant acceleration" hence you had to use the SUVAT equationsFOR QUESTION 2 I JSUT USED AREA UNDER GRAPH, SUVAT WAS NOT NEEDED ON ANY QUESTION ON THE PAPPER!
4500 is correct.Guys i used the Kirchoff's second law for the Resistance of X and i showed them the whole long loop.. But during exam i got a different answer and at home i got 4500. My signs and the loop is on point so i do get 2 marks out of 3 right?
Me tooo pleaseCan we three discuss with each other? in pm?
yes it 4500Guys how did you find the electricity question? Did anyone else get 4500 ohms as the resistance value?
4500 is correct.
I dont understand your question butthe vertical component is only balanced by the tension in that rope rite?
There is a difference between distance and displacement. If you are talking about displacement then B is correct. If you're talking distance then it's A+B+A.-_________- w8 lemme show u an evidence:
I hope now u understand what I did :/ (plz say i did it correctly :/)
I dont understand your question but
weight for me was 55N
while vertical component was 22N (of tension)
so some force must act upwards to balance the forces or otherwise it would fall
thus the force from the wall would have some vertical component
ohh ok got itI dont understand your question but
weight for me was 55N
while vertical component was 22N (of tension)
so some force must act upwards to balance the forces or otherwise it would fall
thus the force from the wall would have some vertical component
Come on guys -_- i just wrote distance in the picture by mistake... Dw i didnt make the same mistake in pprThere is a difference between distance and displacement. If you are talking about displacement then B is correct. If you're talking distance then it's A+B+A.
No object in the universe can decrease distance traveled. It only adds up.
Then it's ok.Come on guys -_- i just wrote distance in the picture by mistake... Dw i didnt make the same mistake in ppr
Try giving ur own data for experiments or ask ur teacher to do that ... and do the whole theory and calculations part with that ... That will help u maintain ur pace during the examThis isn't entirely relevant to the topic, but how are you guys going to go about preparing for paper 3? I'm not sure, all i know is that we can learn the limitations and improvements of an experiment. Anything else?
For almost 10 years, the site XtremePapers has been trying very hard to serve its users.
However, we are now struggling to cover its operational costs due to unforeseen circumstances. If we helped you in any way, kindly contribute and be the part of this effort. No act of kindness, no matter how small, is ever wasted.
Click here to Donate Now