how physics p42?

[DumbIdiot]

well may be they are right but i dont know how to vary the voltage without the use of an omp amp so i drew it

as the temp of the thermistor changes , the p.d across it will also vary.

 

[Irahman]

yeah yo
ur right. it can't induce emf, but only increase it

how did u increase it??

 

[nabeelah]

There was no op-amp, it was a simple potential divider circuit. We were only provided with a thermistor, resistor of 2.5 kilo ohms and a 4V power supply.

where did u write Vout then?

 

[DumbIdiot]

where did u write Vout then?

it was like this 4V --1-- fix resistor --2-- thermistor--3--0v

vout -> 3 to 2

 

[girmal5]

The paper was not so bad.

 

[Royalist_878]

Can't you guys confirm other answers like the energy for the reduced amplitude of 0.6cm and others...?

 

[Irahman]

what did you draw in k.e graph??

 

[nabeelah]

Can't you guys confirm other answers like the energy for the reduced amplitude of 0.6cm and others...?

i thnk the answer is 4mJ

 

[DumbIdiot]

i thnk the answer is 4mJ

just wrote 4. forgot to look at the axis.
was the milli already there or did we have to write 4x10^-3?

 

[Royalist_878]

just wrote 4. forgot to look at the axis.
was the milli already there or did we have to write 4x10^-3?

I wrote 4.0 too...don't remember though if it was mJ or J!!

 

[nabeelah]

i've made this mistake too!!
wrote 4J instead of 4x10^-3 J
my friend told me that the graph was in mJ
and -1 mark baaammm

 

[nabeelah]

it was like this 4V --1-- fix resistor --2-- thermistor--3--0v

vout -> 3 to 2

and if we put the op-amp as a comparator?

 

[DumbIdiot]

and if we put the op-amp as a comparator?

the only devices available were a fixed resistor , a thermistor and a 4v cell

 

[Dark Blade]

what was the wavelength ratio? (de Broglie question)

 

[nabeelah]

what was the wavelength ratio? (de Broglie question)

got 5.46x10^-something :1

 

[DumbIdiot]

the ratio was 0.0234

 

[nabeelah]

are u sure?/
wavelength (p/e)=mass(e/p)?did u get something like that?/

 

[DumbIdiot]

are u sure?/
wavelength (p/e)=mass(e/p)?did u get something like that?/

the two were accelerated by the same force but that doesnt mean that their resulting speeds were the same

u had to use o.5mv^2 = qV
v=(2qV/m)^0.5
if you work this out . u`ll probably end up with
wavelenth (p/e) = (mass e/p)^0.5

 

[nabeelah]

bt it said same potential
doesn't it mean same speed?

 

[DumbIdiot]

from 0.5mv^2 = qV
q(charge) and V(accelerating PD) are the same but m is different , hence v is different