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How was Chemistry unit-5, 19/06/2013

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I think it was c3h8, because then the equation will be c3h8 + 5o2 = 3co2 + 4h2o and so for 50 c3h8 u will need 250 o2 and 150 co2.
 
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What was the products of the reaction between CH3CH2CH2CH2NH2 & H2SO4 and
CH3CH2CH2CH2NH2 & CH3COOH?

I wrote CH3CH2CH2CH2NH3+HSO4- & CH3CH2CH2CH2NH3+CH3COO-

n what was the value of concentration in 2nd last part of the paper? \
1.8 mol/dm3?
 
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What was the products of the reaction between CH3CH2CH2CH2NH2 & H2SO4 and
CH3CH2CH2CH2NH2 & CH3COOH?

I wrote CH3CH2CH2CH2NH3+HSO4- & CH3CH2CH2CH2NH3+CH3COO-

n what was the value of concentration in 2nd last part of the paper? \
1.8 mol/dm3?

i got the same answers !!!!
 
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What was the products of the reaction between CH3CH2CH2CH2NH2 & H2SO4 and
CH3CH2CH2CH2NH2 & CH3COOH?

I wrote CH3CH2CH2CH2NH3+HSO4- & CH3CH2CH2CH2NH3+CH3COO-

n what was the value of concentration in 2nd last part of the paper? \
1.8 mol/dm3?

First answer is Ok but the second is CH3CH2CH2CH2NHCOCH3 & H2O surely
 
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amides r formed when amines react with acid chloride


It should be CH3COONH2CH2CH2CH2CH3 not amide sorry! Thanks for correcting me
propyl ammonium ethanoate like ammonium ethanoate where one of the hydrogen is replaced by propyl group
 
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What do you people think about the grade boundaries? The paper was easy i think but many people did bad.
 
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