how was M1 42

[daviruss]

how was it guys! i did well el7amdella was easy

 

[hussamh10]

how was it guys! i did well el7amdella was easy

Alhamdulillah it went well just could not figure out the last part

 

[XPFMember]

AsSalamoAlaikum Wr Wb..

Make sure not to discuss until 24 hours of the exam. Just saying..

 

[hussamh10]

AsSalamoAlaikum Wr Wb..

Make sure not to discuss until 24 hours of the exam. Just saying..

Okay

 

[mehdi1028]

Much Better than may June 12. Will loose 8-9 marks

 

[leadingguy]

ALHAMDULILLAH IT WENT GOOD m happy that much that it had made me frgt that I am having high fever

 

[AhShun]

It was the easiest paper ever LOL

 

[srijitsharma]

question was easy...
but spoiled a little...
i think i will secured approx 32 marks..
How might the threshold go this time?

 

[iKhaled]

question was easy...
but spoiled a little...
i think i will secured approx 32 marks..
How might the threshold go this time?

spoiled how?

 

[doorman1995]

1. 1090J
2. a=2m/s2 m=0.6kg T=4.8N
3. 10m/s a=0.4m/s2
4. 39N direction 22.6' AC from x direction
5. 0=30' coefficient=0.693
6. gain in KE=344000J driving force workdone= 1220000J
7. distance OA=216m a=-0.72m/s2 u=17.6m/s

 

[daviruss]

1. 1090J
2. a=2m/s2 m=0.6kg T=4.8N
3. 10m/s a=0.4m/s2
4. 39N direction 22.6' AC from x direction
5. 0=30' coefficient=0.693
6. gain in KE=344000J driving force workdone= 1220000J
7. distance OA=216m a=-0.72m/s2 u=17.6m/s

it is 5N for the tension

 

[daviruss]

hmm

1. 1090J
2. a=2m/s2 m=0.6kg T=4.8N
3. 10m/s a=0.4m/s2
4. 39N direction 22.6' AC from x direction
5. 0=30' coefficient=0.693
6. gain in KE=344000J driving force workdone= 1220000J
7. distance OA=216m a=-0.72m/s2 u=17.6m/s

and for number 7 it is no way 17.6 cuz for max speed was 6.4 sooo.. it is 3.2m/s
and for the ke u get the u=4.44 and v=15 so u put in the ke formula and tadaa el7amdella

 

[iKhaled]

1. 1090J
2. a=2m/s2 m=0.6kg T=4.8N
3. 10m/s a=0.4m/s2
4. 39N direction 22.6' AC from x direction
5. 0=30' coefficient=0.693
6. gain in KE=344000J driving force workdone= 1220000J
7. distance OA=216m a=-0.72m/s2 u=17.6m/s

how did u get the last part of the last question ? explain pls

 

[iKhaled]

hmm

and for number 7 it is no way 17.6 cuz for max speed was 6.4 sooo.. it is 3.2m/s
and for the ke u get the u=4.44 and v=15 so u put in the ke formula and tadaa el7amdella

u r making me sad bro cuz that kinetic energy question is easy but i did a simple mistake that would take marks off me..i had one velocty 4.44 and the other one 13.1 instead of 15 for using the acceleration 0.4 instead of 0.2 arghhh

 

[Adhiraj Shinde]

i

it is 5N for the tension

think the last u was 25.2 m/s and not 17.6.

the overall ppr was easy accept for the kinetic energy which was really a tricky one.How was the paper worldwide? i believe the threshold would not be more than 38 for A.

 

[daviruss]

i
think the last u was 25.2 m/s and not 17.6.

the overall ppr was easy accept for the kinetic energy which was really a tricky one.How was the paper worldwide? i believe the threshold would not be more than 38 for A.

dude no way 25.2 for he u th ,ax speedi s 6.4

 

[doorman1995]

it is 5N for the tension

how its 5? look f=ma rite so the downward weight for a was 6-t=0.6x2 so u get 4.8N

 

[doorman1995]

hmm

and for number 7 it is no way 17.6 cuz for max speed was 6.4 sooo.. it is 3.2m/s
and for the ke u get the u=4.44 and v=15 so u put in the ke formula and tadaa el7amdella

the ques said initial speed at 0 so the max speed it said was attained at t s after journey while the ques asked for speed when t=0 when p is at O so it has no link with max speed

 

[iKhaled]

the ques said initial speed at 0 so the max speed it said was attained at t s after journey while the ques asked for speed when t=0 when p is at O so it has no link with max speed

how did u get that speed then if t = 0 so the velocity should be equal to zero according to the equation given ?

 

[doorman1995]

hmm

and for number 7 it is no way 17.6 cuz for max speed was 6.4 sooo.. it is 3.2m/s
and for the ke u get the u=4.44 and v=15 so u put in the ke formula and tadaa el7amdella

no it was not 4.44 or either 15 i guess u qouted the accelerations as speed the ques had give initial and final accelerations not speeds