HOW WAS M1 MATHS PAPER???

[DumbIdiot]

If we integrate it, the distance doesn't come as 8.33. The integration constant value must be zero? How did you do it?

actually it does come to 8.33. remember you have to integrate from 45 to 50

u get something like this : (-2916.666) -(- 2925) which is equal to 8.33

 

[Khan08]

Oh. I didnt integrate with bounds. My bad. Thanks

 

[nabeelah]

i've integrate with c=dist covered from 0 to 45s so got the answer directly but i don't knw why on earth(stressed maybe) i've add this dist with that calculated during 0 to 5 and 5 to 45s!!

 

[nabeelah]

so got total dist and average speed wrong(-2 marks perhaps)

 

[Khan08]

thats all the answers i can remember

1. 2.5N

4. value of p = 6.12N

alpha = 19.4 degrees

distance travelled
part 1 - 8.33 m
part 2 - 117 m(TDT)
average speed - 2.33 ms^-1

value of k 6.25
steady vmax on incline plane - 2.08 ms^-1

6. workdone on B = 7.68j
greatest height = 3.12m ( 2.4 + .72)

7. lift problem - 9.4 m distance
t1- 9072N
t2 - 9000N
t3 - 8910N

force on mass due to floor
Max - 1008N
Min - 990N

Wasn't the answer to Q1 25N?

 

[girmal5]

Nope.
It was 2.5

You might have not included g