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It was about doppler effect asking about the changes to trace
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It was easyHow did it go?
are you talking about question about the source approaching and receeding?What were the answers to that b part of cro and the angle of velocity?
Yup wrote the sameare you talking about question about the source approaching and receeding?
Greater no of wave cycles seen on the cro when the source is approaching since frequency increases. Opposite for decreasing.
What will happen after 24 hrs?STOP DISCUSSING..... Let twenty-four hours be passed... PLEASE ITS A REQUEST.
U should not discuss the paper before that time.....What will happen after 24 hrs?
Why?U should not discuss the paper before that time.....
badrobot14 plz explain this guy about the rules.Why?
get aGuys I screwed up.. Might score a 45/75..
Do you know how much do I need to get in the other papers so I can score an A/B (Taking A level math)
moderator and all huh lol lmaobadrobot14 plz explain this guy about the rules.
which variantPhysics ppr was an easy one expecting high gt
co-efficient of x as 80, then in (ii) it was -40
The equation of the line AB was 3y = -2x + 14
The co-ordinates of B I got (4,2)
The angles I got were 19.5o and 160.5o.
The area of the shaded region was 22.7 cm2
The equation of the tangent line was y = 3/4 x - 9/2
The rate of change of y with time was 0.12 units per second
The volume of the shaded region when rotated about the x axis was 9pi units3.
The minimum number of terms needed to exceed 20,000 was 70
The sum to infinity was 64.8
The angle AOB was 68.2o
p = 2.5 and q = 4
The stationary point was (4,8)
The curve met the line y=6 when the x co-ordinates were 9 and 1
The range of values of k which for which the curve did not intersect the line k>8
The value of x when f(x)+4 = 0 to one dp was x=-1.2
The domain of the inverse of f was the same as the range of f which was -5<= x <= 1.
Bro i think it was not for the line y=6 it was general to find the value of k for which the actual equation had no roots.Where do you get your solutions from? Your teachers? Apart from that I think the range for which the line y=6 does not intersect the line is k>4. I tested plugging in k=5,6,7,8 in the exam and the quadratic had no real solutions... Am I right? Do you recall f(x) with th tan(x) in one of the last questions? Thanks in advance!
Oh yeah sry. Yes I just misread. Luckily not in the exam ! Yes I know it's for the general line. Anyway what about my solution.Bro i think it was not for the line y=6 it was general to find the value of k for which the actual equation had no roots.
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