how was phy P22??

[Dummy36]

how did u guyz find the paper 2day??
phy 22

 

[shressubha]

questions were easy !!!!!!!!!!!!!!! btw cudn't manage time well

 

[mimi5959]

TIME MANAGEMENT PROBLEM! what do you guys think the threshold's gonna be?

 

[shressubha]

hope GT was less!!

 

[ying27kia]

anyone remember the answer for the electric part and speed of wave?
I got 168 ms-1
for the electric part is it I1+I3=I2 ?

 

[Dummy36]

man i think GT z gott b around 37.....
got to du P1 gur nw.... way better than dis one...

 

[mimi5959]

they said that from the maximum displacement to the minimum dislplacement (i.e from the antinode to the node) the distance covered is 6.7 cm... 0.067m
hence the wavelength is (2 x 0.067).... frequency is 2500 Hz... so the speed will be 335 m.s-1

aand yes the answer for the first part of Kirchoff's Law is I2 = I1 + I3

 

[shressubha]

they said that from the maximum displacement to the minimum dislplacement (i.e from the antinode to the node) the distance covered is 6.7 cm... 0.067m
hence the wavelength is (2 x 0.067).... frequency is 2500 Hz... so the speed will be 335 m.s-1

aand yes the answer for the first part of Kirchoff's Law is I2 = I1 + I3

got speed as 310m/s but wait what was time setting?? do u remember??

 

[ying27kia]

they said that from the maximum displacement to the minimum dislplacement (i.e from the antinode to the node) the distance covered is 6.7 cm... 0.067m
hence the wavelength is (2 x 0.067).... frequency is 2500 Hz... so the speed will be 335 m.s-1

aand yes the answer for the first part of Kirchoff's Law is I2 = I1 + I3

they said it's from maximum-minimum-maximum. So 6.7cm is one wavelength
really confused

 

[ying27kia]

anybody know how to prove kinetic energy equation ?
thanks

 

[mimi5959]

they said that from the maximum displacement to the minimum dislplacement (i.e from the antinode to the node) the distance covered is 6.7 cm... 0.067m
hence the wavelength is (2 x 0.067).... frequency is 2500 Hz... so the speed will be 335 m.s-1

aand yes the answer for the first part of Kirchoff's Law is I2 = I1 + I3

got speed as 310m/s but wait what was time setting?? do u remember??

the time setting was 0.1 ms.cm-1

 

[shressubha]

they said that from the maximum displacement to the minimum dislplacement (i.e from the antinode to the node) the distance covered is 6.7 cm... 0.067m
hence the wavelength is (2 x 0.067).... frequency is 2500 Hz... so the speed will be 335 m.s-1

aand yes the answer for the first part of Kirchoff's Law is I2 = I1 + I3

they said it's from maximum-minimum-maximum. So 6.7cm is one wavelength
really confused

maximum refers to node, minimum refers to antinode. This imply that 6.7 is the distance between 2 nodes and not wavelength. thus lambda/2 = 6.7cm

 

[mimi5959]

oh yes sorry!... its the distance between 2 nodes....

 

[Hsmanime]

For no 7, is it okay to write the charge +2, not +2e?

 

[knightrider07]

blank

 

[InvisionFree]

wat were the graphs??
and how does alpha particle lose energy?

Alpha particles have a high ionization power and they lose energy by ionization.

 

[InvisionFree]

I got my values for frequency and wave speed wrong. Evert thing other than that went well. Man, I am worried. Lets just hope A is around 40.

 

[Abdulrab]

can anyone sketch the graph of velocity-time for the first question ???

 

[knightrider07]

blank

 

[matchwhiz]

do anyone remember their last expression on question electricity which worth 2 marks
i got E1-E2=i1r1+i1R1+i3r2+i1(R2/2)