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HOW WAS PHYSICS PAPER 2 AS!!!!!!!!!!!

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For the force-extension graph of Copper, it was below steel right? A straight line passing through origin, but what was the end point, i mean what was the force at .25 mm extension?? was it .65 N or 1.5 N?
 
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For the force-extension graph of Copper, it was below steel right? A straight line passing through origin, but what was the end point, i mean what was the force at .25 mm extension?? was it .65 N or 1.5 N?
thats exactly the question, it depends on the axes
 
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Can anyone plz explain the method to find K.E and P.E
the final KE was 0 so change in KE was the initial KE...(0.5)(o.o5)(8.4)^2=1.76J........for PE change... h must be calculated.... apply s=ut + (1/2)(a)(t)^2.... s=h... a=-9.81.. u=4.2(given).... t can be calculated bu v=u + at.....0=4.2+(-9.81)(t)..... subtract final PE from initial PE u get 2.0J... i think i got this right.........:)
 
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