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It was okay.....not good, not bad....
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I guess expected days were 49days... There were 52*7=364 days in a year and probability was multiplied with 364 days... I got 49days(7weeks)Nearly 24 hours have passed so i'll just post the answers here for all to see:
1.0.222
2. Mean 45.8 sd 14.9
3.that was all diagram and stuff.
4. X=0.81 next 12/31
5. 0.6 was of even even odd and distribution was 1 0.6 2 0.3 4 0.1
6 20,60 and 1210
7.expected days 7 t=37 min and last mean 8.94 sd 2.42
A friend of mine did the same mistake and even i did 49 initially.You should've read the question carefully.It stated he ran once a week,hence in a year he ran only 52 days.He didnt run everyday.I guess expected days were 49days... There were 52*7=374 days in a year and probaility was multiplied with 364 days... I got 49days(7weeks)
rest of all ans of mine are matching urs
Shit .____.A friend of mine did the same mistake and even i did 49 initially.You should've read the question carefully.It stated he ran once a week,hence in a year he ran only 52 days.He didnt run everyday.
Probably 2 marks,one for that mistake and one for the answer.Shit .____.
How much will i lose 4 marks ka tha woh qstn
I'll try toasadalam .. can u kindly tell me what qs 6 was ? i've forgot it .. and is is it possible for u to recall all questions.. nt word to word but just the statemnent without numerical values ? like what the question was about ?
Nearly 24 hours have passed so i'll just post the answers here for all to see:
1.0.222
2. Mean 45.8 sd 14.9
3.that was all diagram and stuff.
4. X=0.81 next 12/31
5. 0.6 was of even even odd and distribution was 1 0.6 2 0.3 4 0.1
6 20,60 and 1210
7.expected days 7 t=37 min and last mean 8.94 sd 2.42
We had to take the range as 1.6 - 10 s on the plot as we had to showcase time not the number of computers.For question 3,did you take the total as 100 when using box and whisker plot??
Because some of my friends took 88
what was ur median , upper and lower quartile?We had to take the range as 1.6 - 10 s on the plot as we had to showcase time not the number of computers.
I think it was 2.6 3.8 and 6.4 or something along these lines.You?what was ur median , upper and lower quartile?
I think I got something similar....I guess I got 2.7 for lower quartile...thanks..I think it was 2.6 3.8 and 6.4 or something along these lines.You?
Yeah 2.6,3.8 and 6.4!I think it was 2.6 3.8 and 6.4 or something along these lines.You?
But my probability was correct 100% only what I did wrong was just multiplying ans with days not with weeksProbably 2 marks,one for that mistake and one for the answer.
Hmm then i think youll lose only one markBut my probability was correct 100% only what I did wrong was just multiplying ans with days not with weeks
I guess finding probability was of two marks and expected days was of 1 mark... Thats how they distributed marks in prev past ppr qstns
question 7 is 6 days you're supposed to round down no matter how big. This is like the o level question were you were asked how many cups can you fill, if its 6.99 its still 6 cups as the 7th wont be filled.Nearly 24 hours have passed so i'll just post the answers here for all to see:
1.0.222
2. Mean 45.8 sd 14.9
3.that was all diagram and stuff.
4. X=0.81 next 12/31
5. 0.6 was of even even odd and distribution was 1 0.6 2 0.3 4 0.1
6 20,60 and 1210
7.expected days 7 t=37 min and last mean 8.94 sd 2.42
I'm done explaining any questions.i have other papers as well.if you really believe in that,wait till the mark schemes come out and we'll find out.question 7 is 6 days you're supposed to round down no matter how big. This is like the o level question were you were asked how many cups can you fill, if its 6.99 its still 6 cups as the 7th wont be filled.
You're overthinking it bro. 7 is the correct answer.question 7 is 6 days you're supposed to round down no matter how big. This is like the o level question were you were asked how many cups can you fill, if its 6.99 its still 6 cups as the 7th wont be filled.
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