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I'm an IGCSE Maths Teacher - Post your questions here.

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0580 oct/nov 2009 p4, question 8 c , iii)
find the number of students represented by 1 cm square on the histogram, how do we solve these type of questions?

and when they ask us to find the height of other colums by giving one value (in histogram) how do we find it? do we just guess?
no guessing
look 1cm^2 area is 1cm * 1cm
so see how much 1cm in x-axis then how much 1 cm in y-axis then multiply out both
 
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no guessing
look 1cm^2 area is 1cm * 1cm
so see how much 1cm in x-axis then how much 1 cm in y-axis then multiply out both

alryt thnkyu! what abt oct/nov 2008 p42 question 6 part b.ii) ?
is there a formula? how do we solve these type of sums?
 
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alryt thnkyu! what abt oct/nov 2008 p42 question 6 part b.ii) ?
is there a formula? how do we solve these type of sums?

frequency density(height of graph)= frequency/classwidth(the difference between 2 intervals)
so 115/2=57.5 but as height of graph is 11.5 means we divide the frequency density by 5
so 35/10=3.5 3.5/5=0.7
26/2=13 13/5 =2.6
24/6=4 4/4 =0.8
 
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Hey, I'm having trouble with number 2, ii on paper 0580/42 may june 2010. I thought there was no way to get the determinant of a matrix that isn't square? On the marking scheme it says 17​
 
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frequency density(height of graph)= frequency/classwidth(the difference between 2 intervals)
so 115/2=57.5 but as height of graph is 11.5 means we divide the frequency density by 5
so 35/10=3.5 3.5/5=0.7
26/2=13 13/5 =2.6
24/6=4 4/4 =0.8

24/6=4 4/4 =0.8 how do we know its 4? i understand that the interval is more than the others
 
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